Question : If the six-digit number 5x2y6z is divisible by 7, 11 and 13, then the value of $(x-y+3 z)$ is:
Option 1: 7
Option 2: 4
Option 3: 0
Option 4: 9
Correct Answer: 7
Solution : A number divisible by 7, 11, and 13 must be of the form $abcabc$ ⇒ $5x2y6z=562562$ According to the question, which gives ⇒ $x = 6, y = 5$ and $z = 2$ So, $(x -y + 3z) = 6 - 5 + 3 × 2 = 7$ Hence, the correct answer is 7.
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Question : If the six-digit number 479xyz is exactly divisible by 7, 11, and 13, then {(y + z) ÷ x} is equal to:
Option 1: $4$
Option 2: $\frac{11}{9}$
Option 3: $\frac{7}{13}$
Option 4: $\frac{13}{7}$
Question : If $x+y+z=13,x^2+y^2+z^2=133$ and $x^3+y^3+z^3=847$, then the value of $\sqrt[3]{x y z}$ is:
Option 1: $8$
Option 2: $7$
Option 3: $-9$
Option 4: $-6$
Question : If $x+y+z=17, x y z=171$ and $x y+y z+z x=111$, then the value of $\sqrt[3]{\left(x^3+y^3+z^3+x y z\right)}$ is:
Option 1: –64
Option 4: –4
Question : If the 7-digit number $x$468$y$05 is divisible by 11, then what is the value of ($x$ + $y$)?
Option 1: 12
Option 2: 14
Option 3: 8
Option 4: 10
Question : If $x+y+z=19, x y z=216$ and $x y+y z+z x=114$, then the value of $\sqrt{x^3+y^3+z^3+x y z}$ is:
Option 1: 32
Option 2: 30
Option 3: 28
Option 4: 35
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