837 Views

if the velocity of particleat x=0 is 510 and coefficient of friction variesaccording to mu =x what will be the maximum coordinate of particle will be


Recommended : Get important details about Manipal University, Jaipur. Download Brochure
shreyasahu 16th Nov, 2019
Answer (1)
Avishek Dutta 26th Dec, 2019

The acceleration is here present because of friction.

Our acceleration here would be -mu*g.

Where mu is the coefficient of friction and g is the gravitational acceleration.

Hence acceleration a=-mu*g=-xg

vdv/dx=-xg

Hence

v^2/2- 510^2/2=-g/2*x^2

Now v is zero so

510=x√g

x=510/√g=161.27



Compare Colleges

College Comparison based on Courses, Placement, Rank, Fee

Compare Now

Know More About

Related Questions

MAHE Manipal M.Tech 2025
Apply
NAAC A++ Accredited | Accorded institution of Eminence by Govt. of India | NIRF Rank #4
Amity University, Noida Law A...
Apply
700+ Campus placements at top national and global law firms, corporates, and judiciaries
Amity University, Noida B.Com...
Apply
Ranked as India’s #1 Not for profit pvt. University by India Today
Amity University, Noida BBA A...
Apply
Ranked amongst top 3% universities globally (QS Rankings)
Chandigarh University Admissi...
Apply
Ranked #1 Among all Private Indian Universities in QS Asia Rankings 2025 | Scholarships worth 210 CR
Amity University | M.Tech Adm...
Apply
Ranked amongst top 3% universities globally (QS Rankings).
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books