Question : If $(9-3x)-(17x-10)=1$, then the value of $x$ is:
Option 1: $1$
Option 2: $–1$
Option 3: $\frac{9}{10}$
Option 4: $–\frac{9}{10}$
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Correct Answer: $\frac{9}{10}$
Solution : Given: $(9-3x)-(17x-10) = 1$ $⇒9-3x-17x+10 = 1$ $⇒-20x+19 = 1$ $\therefore x = \frac{18}{20} = \frac{9}{10}$ Hence, the correct answer is $\frac{9}{10}$.
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Question : If $x+\frac{1}{x}=3$, then the value of $\frac{3x^{2}-4x+3}{x^{2}-x+1}$ is:
Option 1: $\frac{4}{3}$
Option 2: $\frac{3}{2}$
Option 3: $\frac{5}{2}$
Option 4: $\frac{5}{3}$
Question : If $\frac{x}{3}+\frac{3}{x}=1$, then the value of $x^3$ is:
Option 1: 1
Option 2: 27
Option 3: 0
Option 4: –27
Question : If $\sin (x - y) = \frac{1}2$ and $\cos (x + y) = \frac{1}2$, then what is the value of $\sin x \cos x + 2\sin^2x + cos^3x \sec x$?
Option 1: $2$
Option 2: $\sqrt{2}+1$
Option 3: $1$
Option 4: $\frac{3}{4}$
Question : If $x+\frac{1}{x}=0$, then the value of $x^{5}+\frac{1}{x^{5}}$ is:
Option 1: 2
Option 2: –1
Option 3: 1
Option 4: 0
Question : Find the value of the expression $\frac{x^2-1}{x-1}-\frac{x^2-9}{x-3}$.
Option 2: –2
Option 3: –1
Option 4: 2
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