Question : If $x^{2}+\frac{1}{x^{2}} = 98(x>0)$, then the value of $x^{3}+\frac{1}{x^{3}}$ is:
Option 1: 970
Option 2: 1030
Option 3: –970
Option 4: –1030
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Correct Answer: 970
Solution : Given: $x^{2}+\frac{1}{x^{2}} = 98$ We know, $(x+y)^{2}= x^{2}+y^{2}+2xy$ ⇒ $(x+\frac{1}{x})^{2}= x^{2}+\frac{1}{x^{2}}+2(x)(\frac{1}{x})$ ⇒ $(x+\frac{1}{x})^{2}= 98+2$ ⇒ $(x+\frac{1}{x})^{2}= 100$ ⇒ $ (x+\frac{1}{x})= 10$ Now, $x^{3}+\frac{1}{x^{3}} = (x+\frac{1}{x})^{3}-3(x)(\frac{1}{x})(x+\frac{1}{x})$ = $10^{3}-3(10)$ = $1000-30$ = $970$ Hence, the correct answer is 970.
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Question : If $x^2+y^2=29$ and $xy=10$, where $x>0,y>0$ and $x>y$. Then the value of $\frac{x+y}{x-y}$ is:
Option 1: $- \frac{7}{3}$
Option 2: $\frac{7}{3}$
Option 3: $\frac{3}{7}$
Option 4: $-\frac{3}{7}$
Question : If $(x+\frac{1}{x})^{2}=3$, then the value of $(x^{3}+\frac{1}{x^{3}})$ is:
Option 1: 0
Option 2: 1
Option 3: 2
Option 4: –1
Question : If $(x+\frac{1}{x})=–2$, then the value of $(x^7+\frac{1}{x^7})$ is:
Option 1: 1
Option 2: –1
Option 3: 0
Option 4: –2
Question : If $2\sin(\frac{\pi x}{2})=x^2+\frac{1}{x^2}$, then the value of $(x-\frac{1}{x})$ is:
Option 1: $–1$
Option 2: $2$
Option 3: $1$
Option 4: $0$
Question : If $x+ \frac{1}{x} =2$, then the value of $({x}^{99}+ \frac{1}{x^{99}} –2)$ is:
Option 1: –2
Option 2: 0
Option 4: 4
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