Question : If $\frac{4\left[(17)^3-(7)^3\right]}{\left(17^2+7^2+p\right)}=40$, then what is the value of $p$?
Option 1: –119
Option 2: –129
Option 3: 119
Option 4: 129

Question

Question : If $\frac{4\left[(17)^3-(7)^3\right]}{\left(17^2+7^2+p\right)}=40$, then what is the value of $p$?

Option 1: –119

Option 2: –129

Option 3: 119

Option 4: 129

Team Careers360 · Accepted Answer

Correct Answer: 119

Solution : $\frac{4\left[(17)^3-(7)^3 ight]}{\left(17^2+7^2+p ight)}=40$
We know that, $(a^3-b^3)=(a-b)(a^2+ab+b^2)$
⇒ $\frac{\left(17-7) ight(17^2+17 imes 7+7^2)}{\left(17^2+7^2+p ight)}=10$
⇒ $\frac{10(17^2+17 imes 7+7^2)}{\left(17^2+7^2+p ight)}=10$
⇒ $\frac{(17^2+17 imes 7+7^2)}{\left(17^2+7^2+p ight)}=1$
⇒ $17^2+17 imes 7+7^2=17^2+7^2+p$
$ herefore p=17 imes7=119$
Hence, the correct answer is 119.

Exams

Colleges

Predictors

Resources

Quick links

Exams

Colleges & Courses

Predictors

Resources

Exams

Colleges

Predictors & E-Books

Resources

Engineering Preparation

Medical Preparation

Online Courses

Products

Exams

Colleges

Resources

Exams

Colleges

Predictors & Articles

Resources

Exams

Colleges

Predictors

Resources

Exams

Colleges

Upcoming Events

Resources

Exams

Colleges

Resources

Quick Links

Top Streams

Specializations

Resources

Top Providers

Exams

Colleges

Resources

Diploma Colleges

Exams

Colleges

Resources

Exams

Resources

Top Courses & Careers

Colleges

Exams

Upcoming Events

Resources

Other Exams

Exams

Colleges

Top Countries

Student Visas

Exams

Top Schools

Products & Resources

NCERT Study Material

Question : If 4[(17)3−(7)3](172+72+p)=40, then what is the value of p?Option 1: –119Option 2: –129Option 3: 119Option 4: 129

Related Questions

Know More about

Upcoming Exams

Trending Articles around SSC CGL

Download the Careers360 App on your Android phone

Sign In/Sign Up

Question : If $\frac{4 [(17)^{3} - (7)^{3}]}{(17^{2} + 7^{2} + p)} = 40$ , then what is the value of $p$ ?
Option 1: –119
Option 2: –129
Option 3: 119
Option 4: 129