Question : If $l+m+n=0$, then what will be the value of $(\frac{l^2}{mn}+\frac{m^2}{nl}+\frac{n^2}{lm})^2$?
Option 1: 9
Option 2: 16
Option 3: 4
Option 4: 1
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Correct Answer: 9
Solution : Given, $l+m+n=0$ $(\frac{l^2}{mn}+\frac{m^2}{nl}+\frac{n^2}{lm})^2$ $= (\frac{l^3+m^3+n^3}{lmn})^2$ We know, if $l+m+n=0$, then $l^3+m^3+n^3=3lmn$ $= (\frac{3lmn}{lmn})^2$ $= 9$ Hence, the correct answer is 9.
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Question : If $\left(4y-\frac{4}{y}\right)=11$, find the value of $\left(y^2+\frac{1}{y^2}\right)$.
Option 1: $7 \frac{9}{16}$
Option 2: $5 \frac{9}{16}$
Option 3: $9 \frac{11}{16}$
Option 4: $9 \frac{9}{16}$
Question : If $\cos 20°= m$ and $\cos 70°=n$, then the value of $m^2+n^2$:
Option 1: $1$
Option 2: $\frac{3}{2}$
Option 3: $\frac{1}{\sqrt2}$
Option 4: $\frac{1}{2}$
Question : If $\left(3 y+\frac{3}{y}\right)=8$, then find the value of $\left(y^2+\frac{1}{y^2}\right)$.
Option 1: $5\frac{1}{9}$
Option 2: $4\frac{5}{6}$
Option 3: $7\frac{1}{9}$
Option 4: $9\frac{1}{9}$
Question : If $\mathrm{m}-\frac{1}{\mathrm{~m}}=7$, then what is the value of $\mathrm{m}^2+\frac{1}{\mathrm{~m}^2}$?
Option 1: 0
Option 2: 51
Option 3: 53
Option 4: 49
Question : If $\mathrm{N}+\frac{1}{\mathrm{~N}}=\sqrt{3}$, then find the value of $\mathrm{N}^6+\frac{1}{\mathrm{~N}^6}+11$.
Option 1: –11
Option 2: –2
Option 3: 11
Option 4: 9
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