Question : In a circle with a centre at O(0,0) and a radius of 5 cm, AB is a chord of length 8 cm. If OM is perpendicular to AB, then the length of OM is:
Option 1: 2.5 cm
Option 2: 3 cm
Option 3: 4 cm
Option 4: 1 cm
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Correct Answer: 3 cm
Solution : Given , AB = 8 cm We know that the perpendicular from the centre of a circle to a chord bisects the chord. AM = MB = $\frac{1}{2}×8=4$ cm OA = 5 cm From ∆ AOM, OA2 = OM2 + AM2 ⇒ OM $=\sqrt{5^2-4^2}=3$ cm Hence, the correct answer is 3 cm.
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Question : The length of the chord of a circle is 8 cm and the perpendicular distance between the centre and the chord is 3 cm, then the diameter of the circle is equal to:
Option 1: 5 cm
Option 2: 10 cm
Option 3: 3 cm
Option 4: 7 cm
Question : A tangent AB at point A of a circle of radius 6 cm meets a line through the centre O at point B. If OB = 10 cm, then the length of AB (in cm) is equal to:
Option 1: 5
Option 2: 6
Option 3: 4
Option 4: 8
Question : Half of the length of a chord of a circle is 12 cm and the perpendicular distance between the centre and the chord is 5 cm. The radius of the circle is:
Option 1: 12 cm
Option 2: 13 cm
Option 3: 10 cm
Option 4: 24 cm
Question : PQ is a chord of length 8 cm of a circle with centre O and radius 5 cm. The tangents at P and Q intersect at a point T. The length of TP is:
Option 1: $\frac{20}{3}\ \text{cm}$
Option 2: $\frac{21}{4}\ \text{cm}$
Option 3: $\frac{10}{3}\ \text{cm}$
Option 4: $\frac{15}{4}\ \text{cm}$
Question : In a circle, the length of a chord is 30 cm. The perpendicular distance of the chord from the centre of the circle is 8 cm. Find the diameter of the circle.
Option 1: 28 cm
Option 2: 34 cm
Option 3: 17 cm
Option 4: 30 cm
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