Question : In $\triangle $ABC, AD$\perp$ BC and AD2 = BD × DC. The measure of $\angle$ BAC is:
Option 1: 60°
Option 2: 75°
Option 3: 90°
Option 4: 45°
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Correct Answer: 90°
Solution : Given: In $\triangle$ABC, AD$\perp$BC and AD2 = BD × DC. Applying Pythagoras theorem in $\triangle$ADB and $\triangle$ADC, AB2 = AD2 + BD2 ____(i) AC2 = AD2 + DC2 ____(ii) Adding equation (i) and (ii), AB2 + AC2 = AD2 + BD2 + AD2 + DC2 AB2 + AC2 = 2AD2 + BD2 + DC2 AB2 + AC2 = 2 BD × DC + BD2 + DC2 AB2 + AC2 = (BD + DC)2 AB2 + AC2 = BC2 $\triangle$ABC is a right-angled triangle. $\angle$BAC = 90° Hence, the correct answer is 90°.
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Question : In triangle ABC, $\angle$ABC = 15°. D is a point on BC such that AD = BD. What is the measure of $\angle$ADC (in degrees)?
Option 1: 15
Option 2: 30
Option 3: 45
Option 4: 60
Question : In $\triangle$ABC, $\angle$A = $\angle$B = 60°, AC = $\sqrt{13}$ cm, the lines AD and BD intersect at D with $\angle$D = 90°. If DB = 2 cm, then the length of AD is:
Option 1: 3 cm
Option 2: 3.5 cm
Option 3: 4 cm
Option 4: 4.7 cm
Question : In $\triangle ABC$, the internal bisectors of $\angle ABC$ and $\angle ACB$ meet at $I$ and $\angle BAC=50°$. The measure of $\angle BIC$ is:
Option 1: $105°$
Option 2: $115°$
Option 3: $125°$
Option 4: $130°$
Question : In $\Delta ABC,\angle BAC=90^{\circ}$ and D is the mid-point of BC. Then which of the following relations is true?
Option 1: $AD=BD=CD$
Option 2: $AD=BD=2CD$
Option 3: $AD=2BD=CD$
Option 4: $2AD=BD=CD$
Question : If in a $\triangle ABC$, $\angle ABC=5\angle ACB$ and $\angle BAC=3\angle ACB$, then what is the value of $\angle ABC$?
Option 1: $130°$
Option 2: $80°$
Option 3: $100°$
Option 4: $120°$
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