Question : In $\triangle$ABC, two medians BE and CF intersect at the point O. P and Q are the midpoints of BO and CO, respectively. If the length of PQ = 3 cm, then the length of FE will be:
Option 1: 3 cm
Option 2: 6 cm
Option 3: 9 cm
Option 4: 12 cm
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Correct Answer: 3 cm
Solution : Given: PQ = 3 cm The line joining the mid-points of two sides of a triangle is parallel to the third side and half of the third side. So from $\triangle$ABC, we get FE = $\frac{1}{2}×$BC --(1) and from $\triangle$OBC, we get PQ = $\frac{1}{2}×$BC --(2) From equation 1 and 2, we get FE = PQ = 3 cm Hence, the correct answer is 3 cm.
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Question : Three medians AD, BE, and CF of $\triangle ABC$ intersect at G. The area of $\triangle ABC$ is $36\text{ cm}^2$. Then the area of $\triangle CGE$ is:
Option 1: $12\text{ cm}^2$
Option 2: $6\text{ cm}^2$
Option 3: $9\text{ cm}^2$
Option 4: $18\text{ cm}^2$
Question : In a $\triangle ABC$, AD, BE and CF are the medians from vertices A, B, and C, respectively. The point of intersection of AD, BE and CF is called
Option 1: median point
Option 2: orthocentre
Option 3: centroid
Option 4: incentre
Question : $\triangle ABC$ is a triangle. PQ is a line segment intersecting AB in P and AC in Q and PQ || BC. The ratio of AP : BP = 3 : 5 and the length of PQ is 18 cm. The length of BC is:
Option 1: 28 cm
Option 2: 48 cm
Option 3: 84 cm
Option 4: 42 cm
Question : In $\triangle$ABC the height CD intersects AB at D. The mid-points of AB and BC are P and Q, respectively. If AD = 8 cm and CD = 6 cm then the length of PQ is:
Option 2: 7 cm
Option 4: 5 cm
Question : In $\triangle ABC$, D and E are the midpoints of sides BC and AC, respectively. AD and BE intersect at G at the right angle. If AD = 18 cm and BE=12 cm, then the length of DC (in cm ) is:
Option 1: 10
Option 2: 6
Option 3: 9
Option 4: 8
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