Question : If $\triangle A B C \sim \triangle F D E$ such that $A B=9 \mathrm{~cm}, A C=11 \mathrm{~cm}, D F=16 \mathrm{~cm}$ and $D E=12 \mathrm{~cm}$, then the length of $BC$ is:

Option 1: $5 \frac{3}{4} \mathrm{~cm}$

Option 2: $4\frac{3}{5} \mathrm{~cm}$

Option 3: $3\frac{5}{7} \mathrm{~cm}$

Option 4: $6\frac{3}{4} \mathrm{~cm}$

Question : If $\triangle ABC \sim \triangle QRP, \frac{\operatorname{area}(\triangle A B C)}{\operatorname{area}(\triangle Q R P)}=\frac{9}{4}, A B=18 \mathrm{~cm}, \mathrm{BC}=15 \mathrm{~cm}$, then the length of $\mathrm{PR}$ is:

Option 1: 16 cm

Option 2: 14 cm

Option 3: 10 cm

Option 4: 12 cm

Question : In a $\triangle ABC$, if $\angle A=90^{\circ}, AC=5 \mathrm{~cm}, BC=9 \mathrm{~cm}$ and in $\triangle PQR, \angle P=90^{\circ}, PR=3 \mathrm{~cm}, QR=8$ $\mathrm{cm}$, then:

Option 1: $\triangle ABC \cong \triangle PQR$

Option 2: $ar(\triangle ABC)\neq ar(\triangle PQR)$

Option 3: $ar(\triangle ABC) \leq ar(\triangle PQR)$

Option 4: $ar(\triangle ABC)=ar(\triangle PQR)$

Question : $\triangle ABC$ is an isosceles triangle with AB = AC = 15 cm and an altitude from A to BC of 12 cm. The length of side BC is:

Option 1: 9 cm

Option 2: 12 cm

Option 3: 18 cm

Option 4: 20 cm

Question : In an equilateral triangle ABC, D is the midpoint of side BC. If the length of BC is 8 cm, then the height of the triangle is:

Option 1: $5.5 \mathrm{~cm}$

Option 2: $4.5 \mathrm{~cm}$

Option 3: $6 \sqrt{3} \mathrm{~cm}$

Option 4: $4 \sqrt{3} \mathrm{~cm}$