Answers (3)
srihari naidu 20th Jan, 2019

IIT main 92.88 */* please rank

srihari naidu 20th Jan, 2019

IIT mains 72.88 */* , rank please

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Sai 20th Jan, 2019

Hello Naincy Jaiswal..

According to careers360 rank formula,

Rank formula= [(100-total score) * (no of students wrote exam)] /100

No of students attended are 874469.

So your expected rank will be nearly around 1,76,498.

As per previous year jee mains, any rank below 2,00,000 will be qualified for jee advanced.

So according to expected rank of yours, you are eligible for jee advanced.

Hope this helps you. All the best

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