Question : $ riangle PQR$ is right angled at Q. If PQ = 12 cm and PR = 13 cm, find $ an P+\cot R$.
Option 1: $\frac{9}{10}$
Option 2: $0$
Option 3: $\frac{10}{12}$
Option 4: $\frac{12}{10}$

Question

Question : $ riangle PQR$ is right angled at Q. If PQ = 12 cm and PR = 13 cm, find $ an P+\cot R$.

Option 1: $\frac{9}{10}$

Option 2: $0$

Option 3: $\frac{10}{12}$

Option 4: $\frac{12}{10}$

Team Careers360 · Accepted Answer

Correct Answer: $\frac{10}{12}$

Solution :
PQ = 12 cm
PR = 13 cm
By Pythagoras theorem, PR² = PQ² + QR²
13² = 12² + QR²
QR²= 169 – 144 = 25
⇒ QR = 5 cm
$ an P$ = $\frac{5}{12}$
⇒ $\cot R$ = $\frac{5}{12}$
⇒ $ an P+\cot R$ = $\frac{5}{12}$+$\frac{5}{12}$ = $\frac{10}{12}$
Hence, the correct answer is $\frac{10}{12}$.

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Question : △PQR is right angled at Q. If PQ = 12 cm and PR = 13 cm, find tan⁡P+cot⁡R.Option 1: 910Option 2: 0Option 3: 1012Option 4: 1210

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Question : $△ P Q R$ is right angled at Q. If PQ = 12 cm and PR = 13 cm, find $\tan P + \cot R$ .
Option 1: $\frac{9}{10}$
Option 2: $0$
Option 3: $\frac{10}{12}$
Option 4: $\frac{12}{10}$