Question : Marks scored by a student in different subjects are given in the table below
| Subjects | Marks obtained out of 100 |
| English | 55 |
| Hindi | 90 |
| Mathematics | 75 |
| Science | 80 |
| Foreign Language | 90 |
Five marks are to be deducted from each subject due to a shortage of attendance. The net average of the mean, median and mode of the marks obtained is_______.
Option 1: 79.33
Option 2: 77.67
Option 3: 82.66
Option 4: 73
Correct Answer: 77.67
Solution :
According to the question,
5 marks are deducted from each subject.
⇒ New marks will be:
| Subjects | Marks obtained out of 100 |
| English | 55 - 5 = 50 |
| Hindi | 90 - 5 = 85 |
| Mathematics | 75 - 5 = 70 |
| Science | 80 - 5 = 75 |
| Foreign Language | 90 - 5 = 85 |
⇒ Mean = $\frac{50+85+70+75+85}{5}$ = $\frac{365}{5}$ = $73$
Arranging the data in ascending order:
50, 70, 75, 85, 85
⇒ Median = middle term = 75
Now, Mode = Most occurred value = 85
So, the net average of Mean, Median, and Mode = $\frac{73+75+85}{3}$ = $\frac{233}{3}$ = 77.67
Hence, the correct answer is 77.67.
Related Questions
Question : Study the given table and answer the question(s) that follow(s).
The marks obtained by four students A, B, C, and D in Mathematics, Statistics, and Computers are given in the following table.
The marks obtained by four students A, B, C, and D in Mathematics, Statistics, and Computers are given in the following table.
| Students→/Subjects$\downarrow$ | A | B | C | D |
| Mathematics | 60 | 50 | 70 | 75 |
| Statistics | 70 | 45 | 60 | 80 |
| Computers | 80 | 55 | 55 | 75 |
Who among the students has ranked first based on the total marks obtained as per the given table?
Option 1: C
Option 2: D
Option 3: B
Option 4: A
Question : Directions: Study the given pattern carefully and select the number that can replace the question mark (?) in it.
| 28 | 58 | 118 |
| 21 | 44 | 90 |
| 47 | 96 | ? |
Option 1: 194
Option 2: 150
Option 3: 176
Option 4: 188
Question : The following table shows the percentage of marks obtained by five students - V, W, X, Y and Z - in five subjects.
| Subjects → | Maths | Physics | Chemistry | Botany | Hindi |
| Maximum marks → | 300 | 300 | 200 | 100 | 100 |
| Students | |||||
| V | 60 | 80 | 90 | 100 | 95 |
| W | 90 | 70 | 80 | 70 | 40 |
| X | 70 | 90 | 95 | 80 | 75 |
| Y | 80 | 60 | 70 | 95 | 80 |
| Z | 90 | 50 | 80 | 85 | 85 |
What are the average marks, in percentage, obtained by X?
Option 1: 76.5%
Option 2: 80.5%
Option 3: 82.5%
Option 4: 85.5%
Question : Calculate the mean from the following table.
| Scores | Frequencies |
| 0-10 | 2 |
| 10-20 | 4 |
| 20-30 | 12 |
| 30-40 | 21 |
| 40-50 | 6 |
| 50-60 | 3 |
| 60-70 | 2 |
Option 1: 33.4
Option 2: 32.6
Option 3: 35.8
Option 4: 34.2
Question : Study the given table and answer the question that follows.
| Number of children | Number of families |
| 0 | 4 |
| 1 | 22 |
| 2 | 15 |
| 3 | 6 |
| 4 | 2 |
The average number of children per family is :
Option 1: 1.47
Option 2: 1.59
Option 3: 1.23
Option 4: 1.72
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