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Minimum cut off mark in jee main for admission in to CET,odisha.


Snigdha Swain 19th May, 2019
Answer (1)
Aman Kumar 28th Jun, 2019

Dear Snigdha,

The College of Engineering and Technology, Bhubaneswar is a premier engineering institution under the state government in Bhubaneswar, the capital of Odisha, India. According to last few years record the minimum cutoff Rank a General student must have to take admission in CET,Odisha is 567274 AIR after that only a candidate will be able to take admission in the lowest branch of CET i.e Bachelor of Planning and to take admission in the top branch i.e B.Tech Computer Science and Engineering a candidate should must have AIR 48997.

Hope I have cleared you doubt If you have ant other queries the please ask in the comments section.

Best of luck.

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