Answer (1)
gupta.virat1357 6th Sep, 2022
Hello,
The cut off in 2020 to qualify in JEE Main for SC category was 50.1760245 percentile. In 2021 the expected qualifying percentile for SC category will be between 50-55. Based on our JEE Main Rank Predictor tool you need to score minimum 25-30 marks or above to score such percentile. The minimum cutoff to qualify JEE Mains 2019 for the sc category is 31-36 marks . To secure a seat in one of the NITs, IIITs or GFTIs with a Respectable Branch, being from SC Category you must target a SC Rank of atleast 7k. For the SC Rank, the corresponding CRL will be anywhere around 150-160k, and a Percentile Target of atleast 85-86.
Home state - 16406
(98.5 percentile)
Outside state - 8215
(99.2 percentile)
So for home state students a marks of about 135 - 145 , and for outside candidates a marks of about 155 - 165 will get you CSE at NIT Durgapur. But to remind, exact marks requirement may be different in different shifts of paper, as per level of difficulty.
Hope it helps.
( check last year cut off at JoSAA website, link in comment box.)
.
Edit - Some if the comments suggest that above information is not true, regarding marks requirement.
The above answer was put up in 2021, based on marks vs rank data of 2020. But as per present data in 2021 and 2022 , you need at least 25 marks more for getting same ranks. Moreover there is big variation in different shifts of exam , as per difficulty of paper. Even 1520 marks variation is seen in some shifts. So advisable to keep yourself updated on current trends. As of in 2017 closing rank in 1st round was about 9.8k . So for getting in before this you must score at least 200 . So try targeting a base score of about 250 or a bit less according to your preparations . If you even slightly fall from your base score you may still be getting quite decent score of 200+ for getting in your aspired college and branch.
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