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Relation between current density and electric field intensity ? drive


mohdfarhansiddiqui09 26th Aug, 2020
Answers (2)
Nidhi Singh 26th Aug, 2020

Current density J is a vector quantity which is defined as the current flowing per unit area measured in a direction normal to the direction of flow of charge.

|J| = |I|/ A

Substituting the value of I and Vd in this equation |J| = |I|/ A ;

|J|= nAqVd / A

= nq. (qt|E|/ m)

|J| = (nq2t/ m).|E|

The vector J is parallel to the electric field vector.

In the above equation the quantity nq2t/ m is called conductivity σ.

|J| = (nq2t/ m).|E| = σ |E|





1 Comment
Comments (1)
26th Aug, 2020
mam ap tu net dekh kar chaap de ho
ap pura drive kar ke batao naa
please mam
Reply
Riya Kedia 26th Aug, 2020

Hello

Current density J is a vector quantity which is defined as the current flowing per unit area measured in a direction normal to the direction of flow of charge.

|J| = |I|/ A

Substituting the value of I and Vd in this equation |J| = |I|/ A ;

|J|= nAqVd / A

= nq. (qt|E|/ m)

|J| = (nq2t/ m).|E|

The vector J is parallel to the electric field vector.

In the above equation the quantity nq2t/ m is called conductivity σ.

|J| = (nq2t/ m).|E| = σ |E|

Hope this helps

Thank you

3 Comments
Comments (3)
26th Aug, 2020
same tu de ho app
kuch alag drive kar k solve karo
Reply
26th Aug, 2020
mohdfarhansiddiqui09 Hi
This is the proper method for solving this question.
So given this solution
Reply
26th Aug, 2020
Riya Kedia mam Kirchhoff law batayee
first and second law
Reply

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