required concentration of acetate ion?
Answer (1)
15th Oct, 2020
Dear Aspirants ,
If the [acetate ion] = [ acetic acid] then the pH of the buffer is equal to the pKa of the acid The pKa of acetic acid = 4.74. This is the pH you obtained for the buffer.
Therefore the [acetate ion] = 0.20M
Lets begins with example
Molar mass NaC2H3O2.3H2O = 136.08 g/mol
0.65g = 0.65/136.08 = 0.004777 mol dissolved in 25mL solution = 0.025L
Molarity of acetate = 0.004777/0.025 = 0.19 mol / litre or 0.19M solution
That is very close to what was first proposed as the molarity of the acetate ion.
Hope it will helpful
thanks
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