Rudra Sanjay and tiger can complete a piece of work in 48 days 60 days and 72 days respectively they started the work together but after 9 days Tiger left if the Sanju live 6 days before the completing of the work in how many days will the work be completed
Answer (1)
27th Mar, 2020
Hello,
Let the work done by Rudra, Sanjay and Tiger in one day individually be x,y,z respectively.
Therefore, from question, 48x = 60y = 72z. Let this be equation ((1)).
For initial 9 days, work done is 9(x+y+z).
Next 6 days, work done is 6(x+y).
The rest of the days, say M days, work done is M * x.
Adding all these, we get, (M+9+6)x + (9+6)y + 9z.
By using equation 1, convert this into only "x" terms.
Thus we get, (M+9+6+11.2+6)x. This work is equal to the total work, i.e 48x.
Thus, solving for M, we get, (M+32.2)x=48x
M=15.8. Rounded off, we get M = 16 days.
Therefore total days required is 16+9+6= 31 days.
Hope this helps.
Comment for clarification.
Thanks.
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