Hi Aami Sampraday Vasant good afternoon you have got 88.86 percentile in JEE MAIN 2019 which was held on 12th January.According to our rank prediction your rank may vary from 120000 to 140000 you can also check using our link https://engineering.careers360.com/jee-main-rank-predictor.Hope this will surely help you.

Hello

Dear, the final cutoff percentile will be released by NTA after the April exam. So you will have to wait for now to know the cutoff results.
However, you can estimate your rank by the below given formula:
(100 - your percentile) * (874469/100)
Here, 874469 is the total number of students who appeared for the January session of JEE Mains exam.

Accordingly, your rank comes around 98 K. This rank is just an estimated one and it may vary depending upon the number of students appearing in the April exam session of JEE Mains.
As per our expert team, candidates having 85+%ile will qualify for JEE Advanced. Well, this is the predicted range. According to your score, you have chances to qualify for JEE Advanced level.
Hope for the best.!

Good Luck.!

For any further information-queries, you can ask here at Careers360 anytime.!

Hello,
You can yourself calculate your rank from the below given link:
https://www.entrance360.com/engineering/how-to-calculate-rank-for-jee-mains-2019/
Based on your percentile of jee mains, your chances of getting admission in NITs or IIITs is quite low.But prepare for the next paper to secure your seat in top colleges.
Good luck.

Hello Aspirant

It is difficult to predict the predict the rank since the official cutoff and results are not released by NTA but use this formula to predict the rank:

Rank Formula = (100 - your total score) X 874469 /100.

Your rank is 97415 out of 874469 students.but this rank may differ from the official results.you have to wait for April exam because after the April exam is conducted then only the official results are released by national testing agency NTA.


If you have any questions further let me know.
Thank you!!!

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