180 Views

the angular velocity and amplitude of a simple pendulum is omega and A respectively at a displacement x if its KE is T and potential energy isU then the ratio of T to U is


Jayasree Patil 13th Apr, 2020
Answer (1)
KUNAL LANJEWAR 13th Apr, 2020

Hello,

We know that, for Simple Pendulum,

Kinetic Energy = T = [ m.ω^2 ( A^2 − x^2 ) ] / 2

Potential Energy = U = m.ω^2.x^2

Hence, Ratio of Kinetic Energy to the Potential Energy is,

T / U = ( A^2 - x^2 ) / x^2

i.e., T : U = ( A^2 - x^2 ) : x^2

Best Wishes.

Related Questions

Amity University, Noida Law A...
Apply
700+ Campus placements at top national and global law firms, corporates and judiciaries
Amity University, Noida BBA A...
Apply
Ranked amongst top 3% universities globally (QS Rankings)
MAHE Online MBA
Apply
Apply for Online MBA from Manipal Academy of Higher Education (MAHE)
Great Lakes Institute of Mana...
Apply
Admissions Open | Globally Recognized by AACSB (US) & AMBA (UK) | 17.8 LPA Avg. CTC for PGPM 2026
Amity University | M.Tech Adm...
Apply
Ranked amongst top 3% universities globally (QS Rankings).
IBSAT 2025-ICFAI Business Sch...
Apply
IBSAT 2025-Your gateway to MBA/PGPM @ IBS Hyderabad and 8 other IBS campuses | Scholarships worth 10 CR
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books