Question : The area of a triangle is 96 cm2 and the ratio of its sides is 6 : 8 : 10. What is the perimeter of the triangle?
Option 1: 48 cm
Option 2: 56 cm
Option 3: 64 cm
Option 4: 44 cm
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Correct Answer: 48 cm
Solution : Given: The ratio of the length of sides is 6 : 8: 10 and the area of the triangle is 96 cm2. Let the sides be $6x$ cm, $8x$ and $10x$ cm. By heron's formula, Area of triangle = $\sqrt{s(s-a)(s-b)(s-c)}$ where, $s=\frac{a+b+c}{2}$ Here, $s=\frac{6x+8x+10x}{2}=12x$ So, $\sqrt{12x(12x-6x)(12x-8x)(12x-10x)}$ = $96$ ⇒ $\sqrt{12x(6x)(4x)(2x)}$ = $96$ ⇒ $24x^2$ = $96$ ⇒ $x^2 = 4$ ⇒ $x=2$ Now, the Perimeter of the triangle = $2s$ = $24x$ = 48 cm Hence, the correct answer is 48 cm.
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Question : The perimeter of an equilateral triangle is 48 cm. Find its area (in cm2).
Option 1: $81\sqrt{3}$
Option 2: $8\sqrt{3}$
Option 3: $25\sqrt{3}$
Option 4: $64\sqrt{3}$
Question : Let A, B, and C be the mid-points of sides PQ, QR, and PR, respectively, of PQR. If the area of $\triangle$ PQR is 32 cm2, then find the area of $\triangle$ ABC.
Option 1: 24 cm2
Option 2: 16 cm2
Option 3: 32 cm2
Option 4: 8 cm2
Question : The centroid of a $\triangle ABC$ is G. The area of $\triangle ABC$ is 60 cm2. The area of $\triangle GBC$ is:
Option 1: 10 cm2
Option 2: 30 cm2
Option 3: 40 cm2
Option 4: 20 cm2
Question : If the side of an equilateral triangle is 8 cm, then find the area of the triangle (correct to two decimal places).
Option 1: 27.17 cm2
Option 2: 27.27 cm2
Option 3: 27.71 cm2
Option 4: 27.72 cm2
Question : If $\triangle A B C \sim \triangle D E F$, and $B C=4 \mathrm{~cm}, E F=5 \mathrm{~cm}$ and the area of triangle $A B C=80 \mathrm{~cm}^2$, then the area of the $\triangle DEF$ is:
Option 1: 169 cm2
Option 2: 80 cm2
Option 3: 144 cm2
Option 4: 125 cm2
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