11 Views

Question : The base of a triangle is equal to the perimeter of a square whose diagonal is $9 \sqrt{2}$ cm and its height is equal to the side of a square whose area is 144 cm2. The area of the triangle(in cm2) is:

Option 1: 216

Option 2: 72

Option 3: 144

Option 4: 288


Team Careers360 5th Jan, 2024
Answer (1)
Team Careers360 6th Jan, 2024

Correct Answer: 216


Solution : Diagonal of square = $9 \sqrt{2}$ cm
Now, $\sqrt 2$ × side of square = $9 \sqrt{2}$
⇒ Side of square = 9 cm
So, the perimeter of square = 4 × 9 = 36 cm
Base of triangle, $b$ = 36 cm
Area of square = 144 cm2
Also, the side of square = $\sqrt{144}$ = 12 cm
Height of the triangle, $h$ = 12 cm
Now, the area of triangle = $\frac{1}{2}×b×h$
= $\frac{1}{2} × 12 × 36$
= 216 cm2
Hence, the correct answer is 216.

Know More About

Related Questions

Amity Online MBA
Apply
Apply for an Online MBA from Amity Online.
Manipal Online M.Com Admissions
Apply
Apply for Online M.Com from Manipal University
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books