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the body of mass 21kg is dragged on the horizontal rough road with a constant speed of 20km/hr if coefficient of friction is 0.5 find the heat generated in one hour (g=10m/s2 , j=4200j/kcal


psaichaitanyareddy038 1st Aug, 2020
Answers (2)
Abhay Tyagi 1st Aug, 2020

Hello,

Solution for the question is given below:

j=4200j/kcal (given)

g=10m/s2 (given)

Work Done=F*displacement Coefficient of friction*m*g*(v*t)W

=0.5*21*10*(20*36500)

=7,560,000

Heat Generated=7,560,000/4186

=806.02 w

Thank You!



Prabhav Sharma 1st Aug, 2020

Hello,

We know that heat generated by the body will be the total work done by the body.

And, work done by the body is given by the relation, W = Force * Displacement

Also, Force = coefficient of friction * mass * acceleration due to gravity

Therefore, W = coefficient of friction * mass * acceleration due to gravity * displacement (Equation 1)

Now, Coefficient of friction = 0.5 (Given)

Mass = 21 KG (Given)

Acceleration due to gravity = 10 m/s^2 (Given)

Speed = 20 Km/hr, therefore distance travelled in 1 hour will be: 20Km = 20000 m (Given)

Now substituting the values in Equation 1, we get:

W = 0.5 * 21 * 10 *20000 = 2.1 * 10^6 J (Answer)

Also, we know, 1 kcal = 4200 J

Therefore, work done = (2.1 * 10^6) /4200 = 500 kcal (Answer)

Hope it is clear to you!

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