109 Views

the differentiable equation of wave in a vibrating string of mass per unit length m and tightened


Badal Kumar Yadav 19th Dec, 2019
Answer (1)
Abhik Sarkar 20th Dec, 2019

Hello!

this is for the transverse vibration in flexible strings

Let us assume a vibrating string element of length dx

Condition- No bending rigidity, tension is constant

The force on the lower end of the element is T

and the force on the other end is T(θ+∂θ /∂xdx)

Balancing force along y direction

ρ dx y'' = Tsin( θ + θ'dx) - T sinθ

where ρ is the density of the string per unit length y'' is double differentiation of y wrt t and θ is the angle the string makes with the horizontal

θ is very small so sinθ=θ

so

ρ dx y'' = Tsin( θ + θ'dx) - T sinθ

=T (θ + θ'dx) - Tθ

on further simplification we get

ρ y'' = T ∂θ /∂x

Tan θ = ∂y/∂x

θ = ∂y/∂x

ρ y'' = T ∂θ /∂x = ρ d(∂θ /∂x)

So we get

(∂^2y/∂t^2) -c^2 (∂^2y/∂x^2)

c squared is shown as c^2

Hope this clears the doubt.







Related Questions

Amity University, Noida Law A...
Apply
700+ Campus placements at top national and global law firms, corporates and judiciaries
Amity University, Noida BBA A...
Apply
Ranked amongst top 3% universities globally (QS Rankings)
VIT Bhopal University | M.Tec...
Apply
M.Tech admissions open @ VIT Bhopal University | Highest CTC 52 LPA | Apply now
Amity University | M.Tech Adm...
Apply
Ranked amongst top 3% universities globally (QS Rankings).
Graphic Era (Deemed to be Uni...
Apply
NAAC A+ Grade | Among top 100 universities of India (NIRF 2024) | 40 crore+ scholarships distributed
Amity University Noida B.Tech...
Apply
Among Top 30 National Universities for Engineering (NIRF 2024) | 30+ Specializations | AI Powered Learning & State-of-the-Art Facilities
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books