Question : The lengths of the three sides of a triangle are 30 cm, 42 cm, and $x$ cm. Which of the following is correct?
Option 1: $12 \leq x<72$
Option 2: $12>x>72$
Option 3: $12<x<72$
Option 4: $12 \leq x \leq 72$
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Correct Answer: $12<x<72$
Solution : The sum of the lengths of any two sides of a triangle is greater than the third side. Also, the difference in lengths of any two sides of a triangle is smaller than the third side. According to the question, $(30+42)>x>(42-30)$ ⇒ $72>x>12$ ⇒ $12<x<72$. Hence the correct answer is $12<x<72$.
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Question : Possible lengths of the three sides of a triangle are:
Option 1: 2 cm, 3 cm, and 6 cm
Option 2: 3 cm, 4 cm, and 5 cm
Option 3: 2.5 cm, 3.5 cm, and 6 cm
Option 4: 4 cm, 4 cm, and 9 cm
Question : The lengths of the three medians of a triangle are $9\;\mathrm{cm}$, $12\;\mathrm{cm}$, and $15\;\mathrm{cm}$. The area (in $\mathrm{cm^2}$) of the triangle is:
Option 1: $24$
Option 2: $72$
Option 3: $48$
Option 4: $144$
Question : The three sides of a triangle are 5 cm, 9 cm, and x cm. The minimum integral value of x is:
Option 1: 2
Option 2: 3
Option 3: 4
Option 4: 5
Question : Let $0<x<1$. Then the correct inequality is:
Option 1: $x<\sqrt{x}<x^{2}$
Option 2: $\sqrt{x}<x<x^{2}$
Option 3: $x^{2}<x<\sqrt{x}$
Option 4: $\sqrt{x}< x^{2}<x$
Question : In a right-angled triangle, if the hypotenuse is 20 cm and the ratio of the other two sides is 4 : 3, the lengths of the sides are:
Option 1: 4 cm and 3 cm
Option 2: 8 cm and 6 cm
Option 3: 12 cm and 9 cm
Option 4: 16 cm and 12 cm
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