Question : The oxidation number of Nickel in K4[Ni(CN)4] is
Option 1: 0
Option 2: +4
Option 3: –4
Option 4: +8
Correct Answer: 0
Solution : The correct option is 0.
The oxidation number of Nickel (Ni) in K 4 [Ni(CN) 4 ] is 0.
Let "x" be the oxidation number of nickel (Ni). To neutralize the overall charge of the compound (which is 0), the sum of the oxidation numbers of all the elements must equal 0 . Therefore: (+4) - 4(x) - 4 = 0
Solving for,
4 - 4x - 4 = 0;
-4x = 0;
x = 0.
So, the oxidation number of nickel (Ni) in K 4 [Ni(CN) 4 ] is 0.
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