Question : The ratio of the sides of a triangle is 11 : 11 : 4. If the area of the triangle is $2\sqrt{117}$ cm, then what is the length of the equal sides?
Option 1: 3 cm
Option 2: 13 cm
Option 3: 11 cm
Option 4: 9 cm
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Correct Answer: 11 cm
Solution : Given: The ratio of the sides of a triangle is 11 : 11 : 4. The area of the triangle is $2\sqrt{117}$ cm2. A perpendicular bisector in an isosceles triangle bisects the base and acts as the height of the triangle. Let the sides be $11x,11x,$ and $4x$ Then, the height AD = $\sqrt{(11x)^2-(2x)^2}=\sqrt{117x^2}$ Area of a triangle = $\frac{1}{2}$ × Base × Height ⇒ $\frac{1}{2}×4x×\sqrt{117x^2}=2\sqrt{117}$ ⇒ $x^2=1$ ⇒ $x=1$ So, the length of the equal sides = (11 × 1) = 11 cm Hence, the correct answer is 11 cm.
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Question : The ratio of the sides of a triangle is 3 : 3 : 4. If the area of a triangle is $32 \sqrt{5}$ cm2, then what is the length of the equal sides?
Option 1: 12 cm
Option 2: 16 cm
Option 3: 10 cm
Option 4: 15 cm
Question : The longest side of the obtuse triangle is 7 cm and the other two sides of the triangle are 4 cm and 5 cm. Find the area of the triangle.
Option 1: $1 \sqrt{3} \mathrm{~cm}^2$
Option 2: $6 \sqrt{3} \mathrm{~cm}^2$
Option 3: $3 \sqrt{2} \mathrm{~cm}^2$
Option 4: $4 \sqrt{6} \mathrm{~cm}^2$
Question : The lengths of the three sides of a triangle are in the ratio of 2 : 2 : 3. If the perimeter of the triangle is 42 cm, then what is the length of the largest side?
Option 2: 18 cm
Option 3: 20 cm
Question : The larger diagonal of a rhombus is 150% of its smaller diagonal, and its area is 432 cm2. Find the length (in cm) of the side of the rhombus.
Option 1: $8 \sqrt{13}$
Option 2: $4 \sqrt{13}$
Option 3: $6 \sqrt{13}$
Option 4: $2 \sqrt{13}$
Question : The radius of the incircle of a triangle whose sides are 9 cm, 12 cm, and 15 cm is:
Option 1: 9 cm
Option 3: 3 cm
Option 4: 6 cm
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