Question : The sides of a triangle are 8 cm, 12 cm, and 16 cm. What is the area of the triangle?
Option 1: $24 \sqrt{15}~\text{cm}^2$
Option 2: $6 \sqrt{15}~\text{cm}^2$
Option 3: $8 \sqrt{15}~\text{cm}^2$
Option 4: $12 \sqrt{15}~\text{cm}^2$
Correct Answer: $12 \sqrt{15}~\text{cm}^2$
Solution : The sides of the triangle are 8 cm, 12 cm, and 16 cm. Semi perimeter = $\frac{8+12+16}{2}$ = 18 Area of the triangle = $\sqrt{18×(18 - 8)×(18 - 12)×(18 -16)}$ = $\sqrt{18×10×6×2}$ = $\sqrt{2160}$ = $12\sqrt{15}\ \text{cm}^2$ Hence, the correct answer is $12\sqrt{15}~\text{cm}^2$.
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Question : What is the area of a triangle whose sides are of lengths 12 cm, 13 cm and 5 cm?
Option 1: $30 \, \text{cm}^2$
Option 2: $15 \, \text{cm}^2$
Option 3: $40 \, \text{cm}^2$
Option 4: $70 \, \text{cm}^2$
Question : If each side of an equilateral triangle is 12 cm, then its altitude is equal to:
Option 1: $6 \sqrt{3}\ \text{cm}$
Option 2: $3 \sqrt{6}\ \text{cm}$
Option 3: $6 \sqrt{2}\ \text{cm}$
Option 4: $3 \sqrt{2}\ \text{cm}$
Question : In triangle ABC which is equilateral. O is the point of intersection of altitude AL, BM, and CN. If OA = 16 cm, what is the semi-perimeter of the triangle ABC?
Option 1: $8 \sqrt 3$ cm
Option 2: $12 \sqrt 3$ cm
Option 3: $16 \sqrt 3$ cm
Option 4: $24\sqrt 3$ cm
Question : What is the area of a triangle having a perimeter of 32 cm, one side of 11 cm, and the difference between the other two sides is 5 cm?
Option 1: $8\sqrt{30}$ cm2
Option 2: $5\sqrt{35}$ cm2
Option 3: $6\sqrt{30}$ cm2
Option 4: $8\sqrt{2}$ cm2
Question : The ratio of three sides of a triangle is $5: 5: 8$. If the area of triangle is $12\;\mathrm{cm^2}$, then what is the length (in$\;\mathrm{cm}$) of the equal sides?
Option 1: 5
Option 2: 8
Option 3: 6
Option 4: 2.5
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