154 Views

the strengthog magnetic field is increased by 21% the frequency of magnetic needle


Sham Sudar 12th Aug, 2019
Answer (1)
NAVEEN MEENA Student Expert 12th Aug, 2019

Dear student, first of all we will find the time period and 1/T is frequency.

So, we know that the time period of any oscillating thing is given by

T = 2 × pi × sqrt( I/M*B)

Now, frequency, f =1/T

=>(1/2*pi)×sqrt( M*B/I)

Now in the above equation 2*pi, I amd M are constant. Therefore,

f is directly proportional to B.

Now applying the formula -

((f2/f1) - 1)×100 =((B2/B1) - 1)×100

In the question its given that the increase is by 21% so putting this value on the right hand side

((f2/f1) - 1)×100 =10%

So the frequency of magnetic needle will be 10%.

All the best

Hope this helps

Related Questions

Chandigarh University Admissi...
Apply
Ranked #1 Among all Private Indian Universities in QS Asia Rankings 2025 | Scholarships worth 210 CR
TAPMI MBA 2025 | Technology M...
Apply
MBA Admission Open in Technology Management and AI & Data Science | NAAC A++ | Institution of Eminence | Assured Scholarships
Sanskriti University LLM Admi...
Apply
Best innovation and research-driven university of Uttar Pradesh
Maya Devi University LLM admi...
Apply
43.6 LPA Highest Package | 5.48 LPA Average Package | 150+ Courses in UG, PG, Ph.D
Amity University, Noida Law A...
Apply
700+ Campus placements at top national and global law firms, corporates, and judiciaries
Shri Khushal Das University L...
Apply
Approved by UGC | Robust Placement Assistance
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books