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Three consecutive natural numbers are such that the square of the middle no exceeds the difference of the squares of other two by 60findthen


Diya Rautela 5th Mar, 2019
Answer (1)
harsh Student Expert 5th Mar, 2019
Hello Diya
Answer is 9;10;11
Take the numbers as
n-1
n
n+1
Now according to given condition
( n+1)^2 - ( n-1)^2 + 60 = n^2
(n+1+n-1) *( n+1-n+1) +60 = n^2
4*n +60 = n^2
So
n = 10
Good luck.

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