Question : Two chords AB and CD of a circle meet inside the circle at point P. If AP = 12 cm, AB = 20 cm, and CP = 16 cm, find CD.
Option 1: 22 cm
Option 2: 15 cm
Option 3: 21 cm
Option 4: 24 cm
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Correct Answer: 22 cm
Solution : Given: AB = 20 cm, AP = 12 cm, and CP = 16 cm Also, AB = AP + PB ⇒ 20 cm = 12 cm + PB ⇒ PB = 8 cm We know, AP × PB = CP × PD By substituting the values in the above expression, 12 × 8 = 16 × PD ⇒ PD = 6 cm Then, CD = CP + PD = 16 + 6 = 22 cm Hence, the correct answer is 22 cm.
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Question : In the figure, O is the centre of the circle. Its two chords AB and CD intersect each other at the point P within the circle. If AB = 20 cm, PB = 12 cm, and CP = 8 cm, then find the measure of PD.
Option 1: 12 cm
Option 2: 11 cm
Option 3: 22 cm
Option 4: 14 cm
Question : In the following figure, O is the centre of the circle. Its two chords AB and CD intersect each other at point P inside the circle. If AB =18 cm, PB = 6 cm, and CP = 4 cm, then find the measure of PD.
Option 1: 14 cm
Option 2: 18 cm
Option 3: 16 cm
Option 4: 20 cm
Question : In the given figure, the diameter AB and chord CD of a circle meet at P. PT is tangent to the circle at T. If CD = 8 cm, PD = 10 cm, and PB = 8 cm, find AB.
Option 1: 14.5 cm
Option 2: 22.5 cm
Option 3: 12 cm
Option 4: 8 cm
Question : Two chords of a circle, $\overline{\mathrm{AB}}$ and $\overline{\mathrm{CD}}$, meet outside the circle at the point $\mathrm{P}$. If $\mathrm{m}(\overline{\mathrm{AP}})=200 \mathrm{~mm}, \mathrm{~m}(\overline{\mathrm{AB}})$ $=120 \mathrm{~mm}$, and $\mathrm{m}(\mathrm{CP}) = 160 \mathrm{~mm}$, what is the length of $\mathrm{CD}$?
Option 1: 100 mm
Option 2: 75 mm
Option 3: 60 mm
Option 4: 150 mm
Question : A circle touches all four sides of a quadrilateral ABCD. If AB = 18 cm, BC = 21 cm, and AD = 15 cm, then length CD is:
Option 1: 16 cm
Option 2: 14 cm
Option 4: 18 cm
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