Question : Two medians DM and EN of $\triangle$DEF intersect each other at O at right angles. If EF = 20 cm and EN = 12 cm, then what is the length of DM?
Option 1: 20 cm
Option 2: 12 cm
Option 3: 18 cm
Option 4: 15 cm
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Correct Answer: 18 cm
Solution : In $\triangle$DEF, EN is the median. ⇒ EN : GN = 2 : 1 ⇒ EN = 12 cm So, EG = $\frac{2}{3}$ × 12 = 8 cm and GN = $\frac{1}{3}$ × 12 = 4 cm Two medians DM and EN of $\triangle$DEF intersect each other at G at right angles. In $\triangle$EGM using the Pythagoras theorem, ⇒ EM2 = GM2 + EG2 ⇒ 102 = GM2 + 82 ⇒ GM = 6 cm Since DM is a median in $\triangle$DEF, DG : GM = 2 : 1 ⇒ DG = 2GM = 2 × 6 = 12 cm ⇒ DM = DG + GM = 12 + 6 = 18 cm Hence, the correct answer is 18 cm.
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Question : Two medians NA and OB of $\triangle \mathrm{NOP}$ intersect each other at S at right angles. If NA = 15 cm and OB = 15 cm, then what is the length of OA?
Option 1: $5 \sqrt{5} $ cm
Option 2: $7 \sqrt{5}$ cm
Option 3: $6 \sqrt{5}$ cm
Option 4: $3 \sqrt{5}$ cm
Question : Two medians JX and KY of $\triangle \mathrm{JKL}$ intersect each other at Z at right angles. If KL = 22 cm and KY = 12 cm, then what is the length of JX?
Option 1: $6 \sqrt{19} \mathrm{~cm}$
Option 2: $3 \sqrt{57} \mathrm{~cm}$
Option 3: $2 \sqrt{57} \mathrm{~cm}$
Option 4: $4 \sqrt{19} \mathrm{~cm}$
Question : $\triangle DEF$ is right angled at E. EC is the altitude. CF is 18 cm and FD is 26 cm. What is the length of FE?
Option 1: $2\sqrt{13}$ cm
Option 2: $6\sqrt{13}$ cm
Option 3: $12$ cm
Option 4: $15$ cm
Question : In a triangle DEF, DP is the bisector of $\angle D$, meeting EF at P. If DE = 14 cm, DF = 21 cm and EF = 9 cm, find EP.
Option 1: 3.6 cm
Option 2: 5.4 cm
Option 3: 6.3 cm
Option 4: 2.7 cm
Question : Two circles of radii 15 and 18 cm touch each other externally. What is the length (in cm) of the direct common tangent to the two circles?
Option 1: $18 \sqrt{6}$
Option 2: $12 \sqrt{15}$
Option 3: $30 \sqrt{6}$
Option 4: $6 \sqrt{30}$
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