Question : Two pie charts are given below. There are 6 departments in an office. Pie chart 1 shows the number of males in these 6 departments. The number of males in a particular department is shown as a percentage of total number of males in these 6 departments. Pie chart 2 shows the number of females in these 6 departments. The number of females in a particular department is shown as a percentage of the total number of females in these 6 departments. The difference between the number of males in B and C is 600 and the difference between the number of females in D and E is 900. What is the sum of the number of females in A, B, and F and the number of males in D, E, and A?
Option 1: 26,300
Option 2: 29,400
Option 3: 26,800
Option 4: 25,700
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Correct Answer: 26,300
Solution : Given: The difference between the number of males in B and C is 600 and the difference between the number of females in D and E is 900. Male(1%) = $\frac{600}{3}$ = 200 males Females(1%) = $\frac{900}{3}$ = 300 females According to the question, The sum of the number of females in A, B, and F and the number of males in D, E, and A = (10 + 14 + 25) × 300 + (20 + 20 + 18) × 200 = 26,300 Hence, the correct answer is 26,300.
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Question : The pie chart given shows the number of males in 6 departments. The number of males in a particular department is shown in terms of degrees concerning the total number of males in all 6 departments. The number of males in department S is 1080. J = Total number of males in T and P K = Difference between the number of males in P and Q What is the value of J + K?
Option 1: 3600
Option 2: 4800
Option 3: 2400
Option 4: 1200
Question : Two line charts are given below. Line chart 1 shows the ratio of the number of males to the number of females in two companies A and B for the 5 years. Line chart 2 shows the total number of males (both companies A and B) and total number of females (both companies A and B) for the 5 years. What is the ratio of the number of males in company B in Y1 to the total number of females in company A in Y3 and Y5?
Option 1: 117 : 218
Option 2: 117 : 215
Option 3: 129 : 215
Option 4: 119 : 218
Question : The pie chart given below shows the number of tyres for 6 companies. The number of tyres of a particular company is shown as a percentage of the total number of tyres of these 6 companies. What is the sum of central angles formed by the sectors representing tyres of companies F and A?
Option 1: 84°
Option 2: 108°
Option 3: 144°
Option 4: 112°
Question : The pie chart given below shows the production of 6 different factories. The total production of all these 6 factories is 12000. The production of a particular factory is shown as a percent of the total production of all these 6 factories. J1 = The value of average production of P and R. J2 = The value of average production of Q and T. What is the value of (J1 – J2)?
Option 1: 360
Option 2: 420
Option 3: 340
Option 4: 400
Question : The pie chart given below shows the production of 6 different factories. The total production of all these 6 factories is 15000. The production of a particular factory is shown as a percent of total production of all these 6 factories. $J_1$ = The value of average production of factories F3 and F6. $J_2$ = The difference between the production of factory F1 and F4. What is the value of ($J_2 – J_1$)?
Option 1: 385
Option 2: 395
Option 3: 375
Option 4: 305
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