Question : What is the equation of the line whose y-intercept is $-\frac{3}{4}$ and making an angle of $45^{\circ}$ with the positive x-axis?
Option 1: $4x–4y=3$
Option 2: $4x-4y=–3$
Option 3: $3x–3y=4$
Option 4: $3x–3y=–4$
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Correct Answer: $4x–4y=3$
Solution : Given: $\theta = 45^{\circ}$, we have $m$ = $\tan45^{\circ}$= 1 The $y$-intercept is given as $-\frac{3}{4}$. Putting the values into the equation, we get: $y = x–\frac{3}{4}$ Or, $4y = 4x–3$ $\therefore$ $4x–4y = 3$ Hence, the correct answer is $4x–4y = 3$.
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Question : $P(4,2)$ and $R(–2,0)$ are vertices of a rhombus $PQRS$. What is the equation of diagonal $QS$?
Option 1: $x–3y=–2$
Option 2: $3x+y=4$
Option 3: $3x+y=–4$
Option 4: $x–3y=2$
Question : If $\tan (x + y)=1$ and $\cos (x-y)={\frac{\sqrt3}{2}}$, then what is the value of $x$ and $y$?
Option 1: $x = 3^\circ, y = 4.5^\circ$
Option 2: $x = 37.5^\circ, y = 7.5^\circ$
Option 3: $x = 7.5^\circ, y = 37.5^\circ$
Option 4: $x = 4.5^\circ, y = 3^\circ$
Question : What is the value of $\frac{4x^2+9y^2+12xy}{144}$?
Option 1: $(\frac{x}{3} + \frac{y}{4})^2$
Option 2: $(\frac{x}{3} + y)^2$
Option 3: $(\frac{x}{4} + \frac{y}{6})^2$
Option 4: $(\frac{x}{6} + \frac{y}{4})^2$
Question : If $x+\frac{1}{x}=3$, then the value of $\frac{3x^{2}-4x+3}{x^{2}-x+1}$ is:
Option 1: $\frac{4}{3}$
Option 2: $\frac{3}{2}$
Option 3: $\frac{5}{2}$
Option 4: $\frac{5}{3}$
Question : For the triangle $PQR$, find the equation of altitude $PS$, if the co-ordinates of $P, Q, R$ are (1, 2), (2, –1), and (0, 5), respectively.
Option 1: $x–3y=–7$
Option 2: $x+3y=–5$
Option 3: $x–3y=–5$
Option 4: $x+3y=–7$
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