what is the percentile that i have to get to opt for btech cse course in nit surathkal
Hello aspirant,
To get admission in NIT Surathkal a candidate has to get above 99 percentile to get CSE branch. Below is the 2019 JEE MAIN cut-off for NIT Surathkal for CSE branch:
Course Name |
Category |
Male |
Female |
||
Home State |
Other State |
Home State |
Other State |
Computer Science and Engineering |
OBC
2627
623
7857
2295
EWS
1102
248
4610
414
General
3561
2156
4920
3874
SC
1011
285
2337
682
ST
336
105
1403
552
For more information you can visit:
https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-surathkal
Thank you.