Question : What is the radius of the circle that circumscribes the triangle ABC whose sides are 16, 30, and 34 units respectively?
Option 1: 16 Units
Option 2: 17 Units
Option 3: 28 Units
Option 4: 34 Units
Latest: SSC CGL 2024 final Result Out | SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL Tier 1 Scorecard 2024 Released | SSC CGL complete guide
Suggested: Month-wise Current Affairs | Upcoming Government Exams
Correct Answer: 17 Units
Solution : Dimension of triangle = 16, 30, 34 units In triangle ABC, $\because$ 342 = 162 + 302 This means it is a Pythagorean triplet and the triangle ABC is a right-angle triangle. $\therefore$ Radius of circle which circumscribes the triangle ABC= $\frac{\text{Hypotenuse}}{2}$ = $\frac{34}{2}$ = 17 units. Hence, the correct answer is 17 Units.
Candidates can download this ebook to know all about SSC CGL.
Admit Card | Eligibility | Application | Selection Process | Preparation Tips | Result | Answer Key
Question : The midpoints of sides AB and AC of the triangle ABC are, respectively, X and Y. If (BC + XY) = 12 units, then the value of (BC – XY) is:
Option 1: 2 units
Option 2: 6 units
Option 3: 8 units
Option 4: 4 units
Question : D, E, and F are the midpoints of the sides BC, CA, and AB, respectively of a $\triangle ABC$. Then the ratio of the areas of $\triangle DEF$ and $\triangle ABC$ is:
Option 1: $\frac{1}{2}$
Option 2: $\frac{1}{4}$
Option 3: $\frac{1}{8}$
Option 4: $\frac{1}{16}$
Question : ABC is an equilateral triangle. If the area of the triangle is $36 \sqrt{3}$, then what is the radius of the circle circumscribing the $\triangle ABC$?
Option 1: $2 \sqrt{3}$
Option 2: $3 \sqrt{3}$
Option 3: $4 \sqrt{3}$
Option 4: $6 \sqrt{3}$
Question : $D$ and $E$ are points on the sides $AB$ and $AC$ respectively of $\triangle ABC$ such that $DE$ is parallel to $BC$ and $AD: DB = 4:5$, $CD$ and $BE$ intersect each other at $F$. Find the ratio of the areas of $\triangle DEF$ and $\triangle CBF$.
Option 1: $16:25$
Option 2: $16:81$
Option 3: $81:16$
Option 4: $4:9$
Question : ABC is an isosceles right-angle triangle. $\angle ABC = 90 ^{\circ}$ and AB = 12 cm. What is the ratio of the radius of the circle inscribed in it to the radius of the circle circumscribing $\triangle ABC$?
Option 1: $6–\sqrt{2}: 3 \sqrt{2}$
Option 2: $2–\sqrt{2}: \sqrt{2}$
Option 3: $6–3 \sqrt{2}: 1 \sqrt{2}$
Option 4: $6–3 \sqrt{2}: 6 \sqrt{2}$
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile