157 Views

When a certain photosensitive surface is illuminated with monochromatic light of frequency \nu , the stopping potential for the photo current is - \frac{V_{0}}{2} . When the surface is illuminated by monochromatic light of frequency \frac{\nu}{2} , the stopping potential is - V_{0} . The threshold f


Bilal Ahmed 15th Jan, 2020
Answer (1)
priyanshi parekh 15th Jan, 2020


h\nu = W + \dfrac{v_o}{2} ehν=W+2voe

\dfrac{h\nu}{2} = W + v_o e2hν=W+voe

on solving we get, W = 3/2 h \nuW=3/2hν

hv_o = 3/2 h \nuhvo=3/2hν

v_o = 3/2 vvo=3/2v

Related Questions

Amity University, Noida Law A...
Apply
700+ Campus placements at top national and global law firms, corporates and judiciaries
Amity University, Noida BBA A...
Apply
Ranked amongst top 3% universities globally (QS Rankings)
VIT Bhopal University | M.Tec...
Apply
M.Tech admissions open @ VIT Bhopal University | Highest CTC 52 LPA | Apply now
Amity University | M.Tech Adm...
Apply
Ranked amongst top 3% universities globally (QS Rankings).
Graphic Era (Deemed to be Uni...
Apply
NAAC A+ Grade | Among top 100 universities of India (NIRF 2024) | 40 crore+ scholarships distributed
Amity University Noida B.Tech...
Apply
Among Top 30 National Universities for Engineering (NIRF 2024) | 30+ Specializations | AI Powered Learning & State-of-the-Art Facilities
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books