Hi, Calculate your rank of JEE mains 2019 here - https://engineering.careers360.com/articles/jee-main-cutoff-for-top-nits.

If NTA percentile score is 93, JEE Main rank will be (100-93) X 1200000/100 = 84000. Using this estimated calculation, check previous year cut offs and get an idea of the probable colleges. Click on the following link to know the cut off trends for JEE main - https://engineering.careers360.com/articles/jee-main-cutoff

Hello.

The official ranks will be released by NTA after the exam in April. You could predict your rank using this formula:

JEE Main 2019 rank (probable) = (100- NTA percentile score ) X 874469 /100

Since only the best of the two scores will be considered for the final rank list, the rank is bound to vary. Hence, as of now it's quite difficult to predict the colleges you may get allotted into.

Good luck!

It would be difficult to provide the exact information about the admission possibilities & cutoff as first time JEE Main is being conducted twice by NTA in multiple session.

Based on this score your probable rank will be 75,795 - 83,295, Wth this rank you may be eligible for JEE Advance but chances seems less to get a seat in NITs, You can try for other colleges.

NOTE: Rank Predicted is on the basis of the expected total number of students i.e. 1152650 appearing in the JEE Mains April Session.

Good Luck!