Which nit college do I get on the 34527 ranks in the sc category for mechanical engineering
With a category rank of 34527 in the SC category for Mechanical Engineering in the 2025 JEE Main exam, you have a good chance of securing a seat in several National Institutes of Technology (NITs). However, admission to the top-ranked NITs for the Mechanical Engineering branch might be competitive even with the SC category reservation.
Based on the previous year's cutoff trends, particularly for the SC category, you can likely get into some of the newer NITs. These NITs often have lower cutoff ranks compared to the older, more established ones. You might find opportunities in NITs located in states like the North-Eastern states, some of the centrally funded technical institutes (CFTIs), or even some of the state NITs where the closing ranks for the SC category in Mechanical Engineering fall within your rank range.
To give you a more specific idea, you should refer to the JoSAA (Joint Seat Allocation Authority) counseling data from previous years. Look for the closing ranks for the SC category specifically for Mechanical Engineering in each NIT. Websites like Careers360 and Shiksha often compile this data, which can give you a good indication of your chances.
Keep in mind that cutoff ranks can vary each year depending on factors such as the number of applicants, the difficulty level of the exam, and the number of available seats. Therefore, it is crucial to check the official JoSAA counseling website for the most up-to-date information during the counseling process in 2025.
During the JoSAA counseling, it is advisable to fill in as many choices of NITs and their Mechanical Engineering programs as possible, starting from your most preferred to the least preferred options. This increases your chances of securing a seat in one of the NITs based on your rank and category. Good luck with the counseling process!
Visit our College predictor tool:- https://engineering.careers360.com/jee-main-college-predictor?ici=nav-header_engg&icn=jee-main_cp-lp
