301 Views

(X+Y) whole square +(Y+Z)whole square +(Z+X)whole square when X+Y+Z=2 and XY +YZ+ ZX= 1


Aaditya Jha 23rd Apr, 2019
Answer (1)
Aaryan Sood 24th Apr, 2019

Hey Aaditya,

Here’s the solution to the asked problem:-

(X+Y)^2 = X^2 + Y^2 +2XY

(Y+X)^2 = Y^2 + Z^2 + 2YZ

(Z+X)^2 = Z^2 + X^2 +2ZX

(X+Y+Z)^2 = X^2 + Y^2 + Z^2 + 2(XY + YZ + ZX)

Use the above equations to calculate the value. 4th equation could be used for calculation of X^2 + Y^2 + Z^2 and could be substituted in the initial 3 equations for the desired results.

Hope this helps.

Related Questions

Chandigarh University Admissi...
Apply
Ranked #1 Among all Private Indian Universities in QS Asia Rankings 2025 | Scholarships worth 210 CR
TAPMI MBA 2025 | Technology M...
Apply
MBA Admission Open in Technology Management and AI & Data Science | NAAC A++ | Institution of Eminence | Assured Scholarships
Sanskriti University LLM Admi...
Apply
Best innovation and research-driven university of Uttar Pradesh
Maya Devi University LLM admi...
Apply
43.6 LPA Highest Package | 5.48 LPA Average Package | 150+ Courses in UG, PG, Ph.D
Amity University, Noida Law A...
Apply
700+ Campus placements at top national and global law firms, corporates, and judiciaries
Shri Khushal Das University L...
Apply
Approved by UGC | Robust Placement Assistance
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books