JEE Main 2026: Preparation Tips & Study Plan
Latest: JEE Main Previous 10 Year Questions with Detailed Solutions (2016-2025)
New: Still looking for BTech admission? Get experts help to choose right college
Don't Miss: Best Public Engineering Colleges
Hey,
dy/dx for given equation is equal to
=((e^x+e^-x)d/dx(e^x-e^-x)-(e^x-e^-x)d/dx(e^x+e^-x))/(e^x+e^-x)^2
=((e^x+e^-x)(e-(-e^-x))-(e^x-e^-x)(e^x-e^-x))/(e^x+e^-x)^2
=(((e^x+e^-x)^2)-((e^x-e^-x)^2)/(e^x+e^-x)^2
= 4/(e^x+e^-x)^2
which is the required answer.
I hope this helps.
All the best!
B.Tech/B.Arch Admissions OPEN
Download the JEE Main 2026 Preparation Tips PDF to boost your exam strategy. Get expert insights on managing study material, focusing on key topics and high-weightage chapters.
Answer Key | Eligibility | Application | Preparation Tips | Question Paper | Admit Card | Result | Accepting Colleges
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile