Ionic equilibrium is an important concept of chemistry and it was developed by the Swedish chemist Svante Arrhenius. Arrhenius published his work around the year 1887. In his discovery he tell us that understanding the ionic equilibrium is very important because it is very helpful in determining the behavior of electrolytes in the Solutions and also the conductivity and reactivity of electrolytes. Understanding of ionic equilibrium has applications in various fields such as physical chemistry, Environmental science, and industrial processes. The discovery of Arrhenius is also useful in understanding the properties of solutions and in the Acid-base reactions.
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Ionic equilibrium refers to the state in which the concentrations of ions in a solution remain constant over time. It occurs in two types of substances.
Types of substances
Substances are of two types:
Strong Electrolyte: These are much ionized in water, and hence show more conduction. For example, Strong acids like HCI, H2SO4, HNO3, strong bases like MOH, MOH2. For example, KOH, NaOH, etc., and salt of strong acid or strong base like NaCl, CH3COONa, NH4X, etc.
Weak Electrolyte: These are less ionized in water so show less conduction. For example, weak acids like CH3COOH, HCN, H3PO4, H2CO3, weak bases like NH4OH, and their salts like NH2CN, CH3COONH4, etc.
Degree of ionization: It is the extent to which an electrolyte gets ionized in a solvent. It is shown by $\alpha$ or x.
$\alpha=\frac{\text { number of molecules dissociated }}{\text { total number of molecules }}$
$\alpha$ depends on the following factors:
It is the ratio of the rate of forward and backward reaction at a particular temperature or it is the ratio of active masses of the reactants to that of active masses of products at a particular temperature raised to their stoichiometric coefficients. It is denoted by Kc or Kp. The distinction between Keq and Kc is that the expression of Keq involves all the species (whether they are pure solids, pure liquids, gases, solvents, or solutions) while the expression Kc involves only those species whose concentration is a variable (gases and solution). It means Kc is devoid of pure components (like pure solids and pure liquids) and solvents.
For a reaction:
$
\begin{aligned}
& \mathrm{mA}+\mathrm{nB} \rightleftharpoons \mathrm{pC}+\mathrm{qD} \\
& \mathrm{r}_{\text {forward }} \propto[\mathrm{A}]^{\mathrm{m}}[\mathrm{B}]^{\mathrm{n}}=\mathrm{K}_{\mathrm{f}}[\mathrm{A}]^{\mathrm{m}}[\mathrm{B}]^{\mathrm{n}} \\
& \mathrm{r}_{\text {backward }} \propto[\mathrm{C}]^{\mathrm{p}}[\mathrm{D}]^{\mathrm{q}}=\mathrm{K}_{\mathrm{b}}[\mathrm{C}]^{\mathrm{p}}[\mathrm{D}]^{\mathrm{q}}
\end{aligned}
$
We know that at equilibrium
$
\begin{aligned}
& \mathrm{r}_{\mathrm{f}}=\mathrm{r}_{\mathrm{b}} \\
& \mathrm{K}_{\mathrm{f}}[\mathrm{A}]^{\mathrm{m}}[\mathrm{B}]^{\mathrm{n}}=\mathrm{K}_{\mathrm{b}}[\mathrm{C}]^{\mathrm{p}}[\mathrm{D}]^{\mathrm{q}} \\
& \frac{\mathrm{K}_{\mathrm{f}}}{\mathrm{K}_{\mathrm{b}}}=\frac{[\mathrm{C}]^{\mathrm{p}}[\mathrm{D}]^{\mathrm{q}}}{[\mathrm{A}]^{\mathrm{m}}[\mathrm{B}]^{\mathrm{n}}} \quad \text { (at constant temperature) } \\
& \frac{\mathrm{K}_{\mathrm{f}}}{\mathrm{K}_{\mathrm{b}}}=\frac{[\mathrm{C}]^{\mathrm{p}}[\mathrm{D}]^{\mathrm{q}}}{[\mathrm{A}]^{\mathrm{m}}[\mathrm{B}]^{\mathrm{n}}}=\mathrm{K}_{\mathrm{c}}
\end{aligned}
$
The above expression gives us the value of Kc as the activity or the active mass is expressed in terms of the concentrations (c) or the molarity.
1. The set of Ionic species formed by hydration of hydroxyl ions are :
1) $\left(\right.$ correct) $\mathrm{H}_3 \mathrm{O}_2^{-}, \mathrm{H}_5 \mathrm{O}_3^{-}, \mathrm{H}_7 \mathrm{O}_4^{-}$
2) $\mathrm{H}_5 \mathrm{O}_2^{+}, \mathrm{H}_7 \mathrm{O}_3^{+}$
3)Only $\mathrm{H}_3 \mathrm{O}_2^{-}$
4)Only $\mathrm{H}_5 \mathrm{O}_2^{+}$
Solution
As we have learned
Hydronium and hydroxyl ions -
In an aqueous solution the hydronium ion is further hydrated to give species like H5O2+, H7O3+, and H9O4+ similarly hydroxyl ions are hydrated to give several ionic species like H3O2-, H5O3- and H7O4- etc.
Hence, the answer is the option (1)
2. Which among the following is a salt but not a strong electrolyte
1) NaCl
2) KCl
3) $\left(\right.$ correct) $\mathrm{HgCl}_2$
4) NaBr
Solution
Substances that are largely dissociated to form a highly conducting solution in water are strong electrolytes. Almost all other salts are strong electrolytes.
Hence, the answer is the option (3).
3. Which among the following is NOT a weak electrolyte
1) HCN
2) $\mathrm{H}_3 \mathrm{BO}_3$
3) (correct) $\mathrm{RSO}_3 \mathrm{H}$
4) $\mathrm{NH}_4 \mathrm{OH}$
Solution
Substances that dissociate only to a small extent in an aqueous solution forming low-conducting liquid are weak electrolytes. All organic acids are weak electrolytes except Sulphonic acid ().
Hence, the answer is the option (3).
4. The species present in the solution when CO2 is dissolved in water are :
$\begin{aligned} & \text { 1) (correct) } \mathrm{CO}_2, \mathrm{H}_2 \mathrm{CO}_3, \mathrm{HCO}_3^{-}, \mathrm{CO}_3^{2-} \\ & \text { 2) } \mathrm{H}_2 \mathrm{CO}_3, \mathrm{CO}_3^{2-} \\ & \text { 3) } \mathrm{HCO}_3^{-}, \mathrm{CO}_3^{2-} \\ & \text { 4) } \mathrm{CO}_2, \mathrm{H}_2 \mathrm{CO}_3\end{aligned}$
Solution
When $\mathrm{CO}_2$ is dissolved in water then, $\mathrm{H}_2 \mathrm{CO}_3$ is formed and dissociates in the manner as given below
$
\begin{aligned}
& \mathrm{H}_2 \mathrm{CO}_3 \rightleftharpoons \mathrm{H}^{+}+\mathrm{HCO}_3^{-} \\
& \mathrm{HCO}_3^{-} \rightleftharpoons \mathrm{H}^{+}+\mathrm{CO}_3^{2-}
\end{aligned}
$
All of these species will be present at equilibrium.
All of these species will be present at equilibrium.
Hence, the answer is the option (1).
5. Which of the following is the unit of ionic mobility?
1) $m V^{-1} s^{-2}$
2) $m s^{-2}$
3) $m^2 V^{-1} s^{-2}$
4) (correct) $m^2 V^{-1} s^{-1}$
Solution
Ionic Mobility is defined as the speed of an ion under one unit of potential gradient,
$\begin{aligned} & \text { Ionic Mobility }=\frac{\text { Speed of ions }}{\text { Potential gradient }} \\ & \text { Ionic Mobility }=\frac{\mathrm{m} / \mathrm{s}}{\mathrm{V} / \mathrm{m}} \\ & =\frac{\mathrm{m}^2}{\mathrm{Vs}}\end{aligned}$
Ionic equilibrium is the equilibrium established between the unionized molecules and the ions in a solution of weak electrolytes. Ionic equilibrium involves the balance between the dissociation of an ionic compound into its constituent ions and the combination of these ions into the initial compound when an ionic compound dissolves in water, it dissociates into its positive and negative ions. For example, sodium chloride (NaCl) separates into Na⁺ and Cl⁻ ions. Ions in solution can recombine to form the original ionic compound. This process is reversible and depends on the concentration of the ions. In ionic equilibrium we also study the common Ion Effect which is that the presence of a common ion in the solution can change the position of equilibrium, often reducing the solubility of a sparingly soluble salt.
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