Pt Deen Dayal Mahavidyalaya, Ladampura All Questions

Hello Prabhat

Your rank for the given percentile is somewhat around 10,056 approximately according to the formula given by our experts. There may be some deviations possible from this as the total number of students can be known only after the mains exam which will be conducted in April.

If you are not satisfied with this rank then go for the April attempt as well of the paper.

Thanks for contacting us.

All the best!!

Hello aspirant. Thanks for connecting with Careers360. First of all, congratulations for scoring such a good percentile. I would like to tell you that the final cutoffs will be released after April session of JEE MAIN exam. You have to wait till April to know the exact cutoff. However, there are chances that you might get a seat in Jamia Milia considering previous year cutoffs. Hope this answer helps you. Good luck. 

Hello..

The predicted rank formula for paper 2 is 

(100-percentile)*145386/100.

If we implement the above ewith your percentile your approximate rank will be around 18,320.

You have chances of getting the seat in nits.

For more details visit the link:

https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning/amp

All the best..

Thank you for consulting careers360

The calculation of the marks would be difficult, You can check JEE Main paper II answer key with the given below link to take an idea about the marks.

https://engineering.careers360.com/articles/jee-main-paper-2-answer-key

A total No. of 1,45,386 candidates had appeared for January Session, Using the Formula (100-your score)* 1,45,386 / 100-

Your Expected rank will be 1,453.

Good Luck! 

It would be difficult to provide you the exact information about the qualifying score or admission cutoff of NITs as JEE Main is being conducted twice by NTA for the first time.

As a total No. of 1,45,386 candidates had appeared for January Session, Using the Formula (100-your score)* 1,45,386 / 100- Your Expected rank will be 10,177. With this rank chances seems less to get a seat in SPA colleges. You can go through with the given below link to check the previous year cutoff.

https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning

NOTE: This is only a prediction. NTA will merge the scores obtained in first and second attempt by candidates of JEE Main Paper 2 2019 for the compilation and preparation of overall merit/rank list. The rank will be released on 30th April, 2019.

Good Luck!

Hello sakshi

Well, it's very difficult as of now,to predict the cutoff for JEE mains paper 2 based on percentile.You can first calculate your rank by rank=(100-percentile)*145386/100.With this rank,you can compare previous year's cutoff for different colleges and can predict some of the colleges you may be getting.But remember this is not the final rank.It will change based on the april session of mains.Hope this helps.

Good Luck!

Hello dewansh

NTA will release the cutoffs in April so right now we can't predict whether you are eligible but as per the past trends and our experts candidates having percentile above 85 are supposed to be qualified for advance.

So please wait till then and hope for the best.

Thanks for contacting us.