East Point College | B.Com Admissions 2025
ApplyNBA Accredited | AICTE Approved
Search Colleges, Exams, Schools & more
Interested in this College?
Get updates on Eligibility, Admission, Placements Fees Structure
Get updates on Eligibility, Admission, Placements Fees Structure
Filter by Topics
Showing 10 out of 646 Questions
Latest
Hello Gautom,
207 must be your marks in JEE mains paper 2.
In order to get your rank you have to tell your percentile.
So please comment your percentile.
For more details you can get refrence from career 360 website :
https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning
thanks
Hello,
Your rank would be around 46k by using the formula
145000*(100-percentile obtained)/100.
According to last year's cutoff you may not get a seat in any nit or central govt colleges.
Still you have a chance ,work hard for April paper
Good luck!
Your rank would be around 46k by using the formula
145000*(100-percentile obtained)/100.
According to last year's cutoff you may not get a seat in any nit or central govt colleges.
Still you have a chance ,work hard for April paper
Good luck!
Dear aspirant,
Your rank will be nearly (100-68.84)*145386/100=45302 based on previous year trends.And chances are less to be qualified to appear for jee advanced exam as experts predicted cutoff to be nearly 85 percentile for general candidate.
Good luck
Hi Vinslin,
This year a total of 1,45,386 aspirant appeared for the JEE B.Arch Examination. Therefore, basing upon the total number of aspirants the formula for calculating your rank would be ([100-your percentile] x 145386)/100. Therefore, approximately your rank will be around 1163. Calculating marks using percentile is not possible and thus you will have to wait till it is released. To clear any doubts or to know more about JEE B.Arch Results, keep reading Careers 360 using the link given below: Https://engineering.careers360.com/articles/jee-main-paper-2-result
Thanks,
Hi Ishika Soni,
Congratualtions on your succesfull results. This year a total of 1,45,386 aspirant appeared for the JEE B.Arch Examination. Therefore, basing upon the total number of aspirants the formula for calculating your rank would be ([100-your percentile] x 145386)/100. Therefore, approximately your rank will be around 382. Calculating marks using percentile is not possible and thus you will have to wait till it is released. To clear any doubts or to know more about JEE B.Arch Results, keep reading Careers 360 using the link given below:
https://engineering.careers360.com/articles/jee-main-paper-2-result
Thanks,
Hello Ishika,
Congratulations on scoring 99.73 in JEE mains mains paper 2 .
By using this formula :-
(100- your total percentile score) * 1,45,386/ 100.
(Note the rank calculated by this formula is approximate and should not be taken as actual rank, the actual rank by NTA may differ.)
Your rank is about 392 , which is a great rank by which You can easily get into many great Nit's, with the branch you want .
Look ahead to these colleges
1. Dr. B.R Ambedkar Nit.
2.Malviya Nit.
3.Maulana Azad Nit.
4.Motilal Nehru Nit.
I hope this helps.
Thank you.
Congratulations on scoring 99.73 in JEE mains mains paper 2 .
By using this formula :-
(100- your total percentile score) * 1,45,386/ 100.
(Note the rank calculated by this formula is approximate and should not be taken as actual rank, the actual rank by NTA may differ.)
Your rank is about 392 , which is a great rank by which You can easily get into many great Nit's, with the branch you want .
Look ahead to these colleges
1. Dr. B.R Ambedkar Nit.
2.Malviya Nit.
3.Maulana Azad Nit.
4.Motilal Nehru Nit.
I hope this helps.
Thank you.
Hello arjun,
Congratulations for your performance
Total number of students appeared for jee main 2 paper id 180000.
So you can calculate your rank by this method:
180000×(100- obtained percentile)/100
By this your rank would be around 34000.
Good luck
Dear aspirant ,
Firstly congratulations for the result you have got. You can calculate your rank using Rank Formula = (100 - your total score) X 145386 /100.your rank is around 27623
Thank you
Firstly congratulations for the result you have got. You can calculate your rank using Rank Formula = (100 - your total score) X 145386 /100.your rank is around 27623
Thank you
Hi,
Your percentile are very less for government college. You can go through the link provided below for more details .
All the best !!
https://engineering.careers360.com/jee-main-college-predictor
https://engineering.careers360.com/articles/jee-main-rank-list
https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning
Hello aspirant,
Thanks for contacting careers360.
As you belong to general category your Percentile is low.it is not possible to predict the college until nta declares the results for both the exams in April. Better concentrate on April exam and increase your Percentile. To know the college you get use this link.
https://engineering.careers360.com/jee-main-architecture-college-predictor
In case of any more queries feel free to contact. Thank you!
Thanks for contacting careers360.
As you belong to general category your Percentile is low.it is not possible to predict the college until nta declares the results for both the exams in April. Better concentrate on April exam and increase your Percentile. To know the college you get use this link.
https://engineering.careers360.com/jee-main-architecture-college-predictor
In case of any more queries feel free to contact. Thank you!
Have a question related to Pt Deen Dayal Mahavidyalaya, Ladampura ?
Articles
Applications for Admissions are open.
MAHE M.Com Admissions 2025
ApplyAccorded Institution of Eminence by MoE, Govt. of India | NAAC A++ Grade | Ranked #4 India by NIRF 2024
Pearson | PTE
ApplyTrusted by 3,500+ universities and colleges globally | Accepted for migration visa applications to AUS, CAN, New Zealand , and the UK
IIC Lakshya CMA Course
ApplyBe a part of the largest Cost & Management Accounting Body
MAHE, B.Com Admissions 2025
ApplyAccorded Institution of Eminence by MoE, Govt. of India | NAAC A++ Grade | Ranked #4 India by NIRF 2024
Sanskriti University B.Com Admissions 2025
ApplyBest innovation and research-driven university of Uttar Pradesh
Back to top