Pt Deen Dayal Mahavidyalaya, Ladampura All Questions

Hello aspirant, well done. 98.86 is a good score

Based on your score and previous year trends your rank will be nearer to (100−98.86)×1,45368/100=1657.You can have chances with the following colleges

NIT Rourkela

NIT patna

NIT raipur

Moulanam a ad NIT

Malavya NIT 

SPA delhi

Based on previous year cutoffs. For cutoffs of other reputed colleges you may have chance, go to

https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning/amp

hey,

according to you percentile your rank is 1454. But this is just a rough estimate. This might differ from the ranks announced by NTA in april. So wait for april to get the final result. For now nothing can be predicted. The april session exam will affect you rank too.

hope this is helpful to you.

The exact prediction would be difficult as JEE Main is being conducted twice by NTA for the first time. As a total No. of 1,45,386 candidates had appeared for January Session, Using the Formula (100-your score)* 1,45,386 / 100- Your Expected rank will be 8,199. With this rank the chances seems less to get a seat in NITs but other colleges you can try. You can also prefer the previous year cutoff to take an Idea about the admission possibilities.

https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning

NOTE: This is only a prediction. NTA will merge the scores obtained in first and second attempt by candidates of JEE Main Paper 2 2019 for the compilation and preparation of overall merit/rank list. The rank will be released on 30th April, 2019.

Good Luck!

Hello.

Congratulations on your good performance in the examination. You can expect a rank of about 2500, this rank may change as the NTA will consider only the best score of the two exams for final rankings. You could get admission into NITs with your ranking.

Refer this link for previous year cutoffs:

https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning/amp

Good luck!

It would be difficult to provide you the exact information about the qualifying marks or rank as JEE Main is being conducted twice by NTA for the first time. As a total No. of 1,45,386 candidates had appeared for January Session, Using the Formula (100-your score)* 1,45,386 / 100- Your Expected rank will be 89,703. With this rank the chances seems less to be qualify the exam.

NOTE: This is only a prediction. NTA will merge the scores obtained in first and second attempt by candidates of JEE Main Paper 2 2019 for the compilation and preparation of overall merit/rank list. The rank will be released on 30th April, 2019.

Good Luck!

Hello. It is not possible to predict your marks or percentage from your percentile now. Your percentile means the percentage of total no. of students equal to or have scored more than you. But your probable rank can be predicted if you can provide me with your percentile.

Hope this helps. For further queries comment down below.

Good luck!

Hello Prabhat Ranjan,

You Rank according to your percentile is 38295

You can use the formulae given below to calculate the rank -

Rank Formula = (100 - your total score) X 145386 /100. 

145386 are the number of candidates appeared for the examination.

Hope this will help you!

All the best!

Thanku.