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Hello Vishnu,
Since, percentile procedure started so recently so it is still quite difficult for us to predict which college a candidate might get but we can help you out by providing the rank that you might be able to fetch with the percentile mentioned by you and following that I will be providing you a link where you can check out the opening and closing ranks trends of the previous year for different colleges.
Since approximately around 145386 students appeared for JEE B. Arch exam so the rank can be predicted from the given formula -
(100- your total percentile score) * 1,45,386/ 100.
So, accordingly, your rank is somewhere around 28,263 - 28,264 when calculated with the percentile given by you. But, this is a rough evaluation so it is best that you wait till the final rank list is announced by NTA. Along with the result of JEE Main Paper-2 April session, authorities will also release the rank list.
For more details, you can go through the following link -
Https://engineering.careers360.com/articles/jee-main-paper-2-result
Good luck!
Hello Swagata
Congrats for scoring 90.9 percentile in JEE main paper 2.
We can't say that what NIT you wil get but we can predict the rank with this percentile .
There is a pedicted formula from our team to predict rank
Total No of students = 145386
Formula
Probable Rank= ( 100 - your NTA percentile ) x 145386 / 100
So your predicted rank =21807 approx
Our Team predicted that the qualify cutt off would be above 85 percentile .But it just a prediction .So pleae wait till april.
Your have scored very good percentile so according to me you will get admission in following NIT's...
National Institute of Technology, Tiruchirapalli, Tamilnadu
National Institute of Technology, Warangal, Andhra Pradesh
National Institute of Technology, Surathkal, Karnataka
Moulana Azad National Institute of Technology, Bhopal, M.P
Motilal Nehru National Institute of Technology, Allahabad, U.P
National Institute of Technology, Calicut, Kozhikode, Kerala
National Institute of Technology, Durgapur, West Bengal
National Institute of Technology, Hamirpur, Himachal Pradesh
Malaviya National Institute of Technology, Jaipur, Rajasthan
Dr. B R Ambedkar National Institute of Technology, Jalandhar, Punjab
I hope you get my point.
Good Luck!!!
Hi Mannava,
This year a total of 1,45,386 aspirant appeared for the JEE B.Arch Examination. Therefore, basing upon the total number of aspirants the formula for calculating your rank would be ([100-your percentile] x 145386)/100. Therefore, approximately your rank will be around 58,154.
Considering the rank of 58,154, chances of getting a college is very bleak. However, depending upon your category and state quota, you can decide your yourself after having a look at last year's allotment list with opening and closing rank. Use the link given here (https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning#).
To clear any doubts or to know more about JEE B.Arch Results, keep reading Careers 360 using the link given below:
Https://engineering.careers360.com/articles/jee-main-paper-2-result
Thanks,
Hello Vansh..
Thanks for contacting Careers360..
The eligibility criteria is mandatory to follow and nothing can be done regarding that..
Work hard for the next time ..
Hope you understand
All the best:)
Hello Gokul,
You can easily check the colleges in Tamil Nadu with their ratings which will help you choose the appropriate college for yourself.
Also, you can explore the college details i.e courses offered, fee structure, exams and cutoff, placements and many more by simply clicking on college name.
https://engineering.careers360.com/colleges/ranking/2018/top-engineering-colleges-in-tamil-nadu
Hope this helps.
Hello.
You could use this link to know the colleges accepting Jee paper 2 scores along with previous year cutoffs:
https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning
Good luck!
See the admission process is totally dependent on the cutoff,that changes every year.The cutoff can be announced only after the final annoucement of the results by NTA, i.e.after April,2019.To know more about the cutoff,pl plea check the following link:-
https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff/amp
You can get a rough idea about the cutoff from the previous years cut-offs.
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