Correct Answer: 114

Solution : Given:
9 ÷ 576 × 24 + 109 – 7 = ?

After interchanging + with –, and × with ÷, the equation will be as follows –
= 9 × 576 ÷ 24 – 109 + 7
= 9 × 24 – 109 + 7
= 216 – 109 + 7
= 223 – 109
= 114

So, 114 is the required answer to the given equation. Hence, the first option is correct.

Hello,

If you are looking forward to pursue B.tech in Computer Science from a reputed or from a top college with great facilities and high placements, then you will have to give entrance exams. To apply to colleges or universities in India, you need to score highly on entrance exams like JEE Mains, SRMJEE, MU-OET, etc. If you are ready to settle for average colleges then there are multiple options available.

Please check out the link below for colleges without entrance exams:

https://engineering.careers360.com/articles/btech-college-in-india-without-entrance-exam-fees-structure-fsa

Hope this helps,

Thank you

Correct Answer: 3 units

Solution : Let one side of a right-angled triangle be $x$.
Shortest side = $x-1$
Longest side = $x +1$
Since the three sides form a right-angled triangle.
$(x+1)^2=(x-1)^2+x^2$
⇒ $x^2+1+2x=x^2+1-2x+x^2$ 
⇒ $x^2=4x$
⇒$x=4$
Thus, shortest side = $x-1=4-1=3$
Hence, the correct answer is 3 units.

Correct Answer: 7.84

Solution : $\frac{2.5 \times 2.5+0.3 \times 0.3+5 \times 0.3}{1.6 \times 1.6+0.6 \times 0.6-1.2 \times 1.6}$
= $ \frac{2.5 \times 2.5+0.3 \times 0.3+2 \times 2.5 \times 0.3}{1.6 \times 1.6+0.6 \times 0.6-2 \times 0.6 \times 1.6}$
= $\frac{(2.5 + 0.3)^2}{(1.6-0.6)^2}$
= $\frac{2.8^2}{1.0^2}$
= $7.84$
Hence, the correct answer is 7.84.

Correct Answer: Access to specialized skills and expertise

Solution : The correct answer is (c) Access to specialized skills and expertise

One advantage of outsourcing is access to specialized skills and expertise. When companies outsource certain tasks or functions to external organizations or individuals, they can tap into the knowledge and capabilities of specialized service providers.

Outsourcing allows businesses to leverage the expertise of professionals who are dedicated to specific areas of work. These service providers often have in-depth knowledge, experience, and resources focused on the outsourced function. By outsourcing to such providers, companies can benefit from their specialized skills and stay updated with the latest industry trends and best practices.

Correct Answer: 45

Solution : (A + B)'s 1 day's work = $\frac{1}{27}$
C's 1 day's work = $\frac{1}{75}$
(A + B + C)'s 1 day's work = $\frac{1}{27}+\frac{1}{75} = \frac{34}{675}$ ---(1)
A's 1 day's work = $\frac{1}{2.4}$(B + C)'s 1 day's work ---(2)
$\frac{3.4}{2.4}$(B + C)'s 1 day's work = $\frac{34}{675}$
⇒ (B + C)'s 1 day's work = $\frac{24}{675}$
A's 1 day work =$ \frac{34}{675}- \frac{24}{675}=\frac{10}{675}$
we know (A + B)'s 1 day's work = $\frac{1}{27}$
$\therefore$  B's 1 day's work will be = $\frac{1}{27} - \frac{10}{675}$
$\therefore$ B can do the whole task in $=\frac{{15}}{{675}}= 45$ days
Hence, the correct answer is 45.

Hello,

Yes, it's possible to do Chartered Accountancy after completing a B.Tech in CS Engineering. Many people choose to switch fields and explore different career paths. It might require some additional studies and exams, but it's definitely doable. You can pursue CA after engineering. you have to know that CA is considered to be the most difficult stream in commerce. It usually takes 5 years to complete the degree. It can take more than that also.

Hope this helps you,

Thank you

https://dqxeclau.top/careers/chartered-accountant

Hello aspirant,

Candidates can learn about the kinds of questions asked in the exam, the format of the question papers, and the exam's difficulty level by consulting the CS Executive previous year question papers. It is recommended that candidates thoroughly review for the CS Executive 2023 examinations by working through the question papers.

To get the previous year question papers, you can visit our website by clicking on the link given below.

https://finance.careers360.com/articles/cs-executive-question-papers

Thank you

Hope this information helps you.

Hello aspirant,

Candidates must pass the higher secondary exam or complete class 12 with PCM as a required subject in order to be eligible to register in any diploma or degree programme in mobile application development. A student can pursue a profession in mobile application development after earning a BTech in computer science engineering.

So if you fulfill this eligibility criteria you can do mobile application development course.

Thank you

Hope this information helps you.