Admission to the Bachelor of Science (Research) Programme - 2020 in Indian Institute of Science (IISc) will be based on the merit list of JEE Main - 2020 or JEE Advanced - 2020 . Minimum percentage required in these examinations are 60% for General, 54% for EWS, 54% OBC-NCL and 30% for SC or ST or PwD category candidates.

Candidates can apply online on the official website (https://admissions.iisc.ac.in/Web/SelectUGPG.aspx) for admission. Application was started on 2 February 2020 and will closed on 30 April 2020 .

Almost 20-25 correct answers with no negative marking.....very rough estimation though

Chaithanya, while it is difficult to estimate your category rank, you can calculate your approximate rank in the Common Rank List for JEE Mains using your percentile through the following formula:

(100-your total percentile) x 869010/100

So with 94.1463772 percentile, your rank would be around 50868.

Also, if the number of students increases to 12 lakh in the April session, the formula for rank calculation would change to:

(100-your total percentile) x 1200000/100

Hence your expected rank in this case would be around 70243.

Now with this rank you can easily qualify for JEE Advanced and also get into NITs and IIITs based on your category. You might also sit for the April session to increase your score and hence, chances of getting into a top college.

You can also go through our college predictor to check which colleges you are eligible for through your JEE Mains score. The link for the college predictor is: https://engineering.careers360.com/jee-main-college-predictor

All the best.

Hello Aspirant,

It would be difficult to tell you about the qualifying cutoff. But a score of more than 85 you should have decent chance to qualify the exam as General Category.

You may calculate your expected rank by this formula

100 - your total percentile score is the percentage of people ahead of you. 874469 are the number of candidates appeared for Jan exam. So rank formula is (100 - your total score) X 869010 /100. If the number of candidates for April exam increased to 1200000 then your final rank shall be (100 - your total score) X 1200000/100

Good Luck!

Hi dear,

Your son got 97.02 percentile that means his rank is around 25896. If number of student in April month exam will increase then rank will also increase. You can also calculate your rank as

Rank=(100-your percentile)×869010÷100.

You can predict your college here

https://engineering.careers360.com/jee-main-college-predictor

Hope it helps.