JEE Main Paper 1
Hello Ansh,
For your score of 62 marks in jee mains paper1 you may expect your percentile between 87.34180397 - 82.68016383. this percentile is estimated based on the previous year estimates and it might vary a little.
here is the link for your reference:
https://engineering.careers360.com/articles/jee-main-marks-vs-percentile
Hope the answer is helpful.
All the best.
hello candidate,
please use the rank predictor given below to get your percentile of jee main 202
https://engineering.careers360.com/jee-main-rank-predictor
hope it helps.
thank you
You have not mentioned which exam you are talking about but since JEE Mains was conducted on this date and in shifts, I am assuming you are asking about that. If not, please mention the exam in the comments section.
The official answer key for JEE Mains January session is supposed to be released today on their official website. Till then, you can go through this year's JEE Mains question papers and answer key released by experts from the given link: https://engineering.careers360.com/articles/jee-main-answer-key/amp
You can find the slot wise question papers and answer key there. For 9th January morning session question paper and answer key, visit: https://learn.careers360.com/engineering/jee-main-2020-question-paper-with-solution-jan-9th-first-shift/
Hello Taj,
JEE mains paper 1 is for engineering branch only that is BTech or BE. But, paper 2 is for admission in BArch course. To get admission in architecture colleges you either can answer either JEE mains paper 2 or NATA or you can answer both. But, JEE mains paper 1 is not required. You have to answer only paper 2.
Good luck!
Hello dear,
Jee's main paper1 - consists of a B-tech degree i.e ( bachelor of technology ).
Jee main paper 2 consists of b-arch i.e you're (bachelor of architecture).
Many famous monuments were designed by our architect-engineer.
Thanks
Hope this will help you.
Hello,
Your percentile is low which will make your rank very large as 22% of appeared candidates are ahead you. This will make you not eligible for top colleges.
As you mentioned you belong to SC category, your categorical rank will make you open for more college options and it depends on the rank value which colleges will be eligible for you.
results are declared so you can check your rank and score from the result page of NTA. YOu can get an admission into CSE but you have to lose all the top colleges which will make you eligible for admission in non-technical branches or core branched but less possibility to core branch.
If you want to join CSE then look for top private college in your state or outside of the state and join. CSE is a trending branch so there is high demand for it. But in real there is no branch barrier. Students from any branch can work in any domain but skill must be there. without skill no job is given.
Hope it helps!
Hello Satyam,
Every year the cut-off marks for the nit exam will be changing depending on the number of students writing the exam and the difficultly level of the paper .According to the previous years to get seat in the Delhi government college ,you should get less than 10000 rank in the jee mains exam .
Hope this helps you...
Hey!There,
Writing online entrance examination is simpler in comparison to pen paper mode as you don't have to fill up bubble there and this takes lot of time.And aso you can rectify your answer.You don't need to do anything just follow instructions of desktop.White papers will be provided there for calculations.You can marks any question for review if you are not sure that time ..Try to appear in mock test before appearing in real test.That will give you lot of idea.
Ask if any query.
Dear student ,
The jee main 2020 is going to be conducted in the month of January on 6 to 11 , so I hope you are well prepared with your concepts . Coming back to your question , in ST category the minimum percentile you need to score to get perfectly into an NIT is 92 percentile .
By studying the last year's opening and closing rank of all the NITs your minimum rank being in ST category is required to be around 20456 as this is the closing rank of an NIT and the lowest branch like ceramic engineering and food processing engineering along with it .
So best of luck for your future
If you have any query regarding this then mention it in comments section.
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