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JEE Main Paper 1

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243 Views

what is the passing marks for JEE main paper 1 just pass mark only

sheemaashraf123 11th Nov, 2021

It depends upon the JEE Main and JEE Advance cut offs, If You manage to qualify the exam by achieving the cut off, You can apply for JOSAA Counselling. It should be noted the cut off for EWS/SC/ST/FEMALES/OBC category is lower than the general category
However It is usually advised to fill the choices as per the preference of colleges and departments, for example CSE in NIT Trichy is your priority followed by CSE in NIT Warangal, you can fill CSE at NIT Trichy at serial number 1 and CSE at NIT Warangal at serial number 2 and so on and so forth. However to get any NIT, you must have qualified JEE Mains and to get any IIT, you must have qualifies JEE Advanced

But the previous cut offs of colleges should be taken in consideration, it is better to research over the cut off of colleges then make a preference list of colleges and fill accordingly

For the college preferences and the courses provided by these colleges and to know which colleges participate in the JOSAA counselling, please go to the below mentioned link: https://engineering.careers360.com/articles/josaa-participating-institutes/amp

62 Views

jee main paper 1 rank prediction

chandni deb 28th Jun, 2021

Dear Aspirant,

you may use the link provided below to help you predict your respective rank for JEE Mains paper 1 examinations. However, kindly note that the ranking for each year may differ due to various reasons such as the number of candidates appearing for the examination, number of seats available, complexity of the question paper etc. Hence, the link below will help you predict your approximate rank as per the statistics of the particular year.

https://engineering.careers360.com/jee-main-rank-predictor

169 Views

i got 80 percentile in jee main paper 1 and belongs to sc category can i get seat into any nit or iiit in cse/IT branches ??

shreyakhedkar05 10th Aug, 2021

Hello,

The admission to NITs and IIITs are based on the cutoff ranks. Percentile couldn't predict the college. Seeing last year's trend of jossa round 1 the cutoff for several colleges is given below.

1.NIT Jalandhar(SC closing rank 9894)

2.NIT Raipur(SC closing rank 11166)

3.NIT Jaipur (SC closing rank 2719)

4.NIT Sikkim (SC closing Rank 70646)

5.NIT Bhopal (SC closing rank 3433)

6. NIT Arunachal Pradesh (SC closing rank 25601)

7.NIT Allahabad(Sc closing rank 1074)

8.NIT Jamshedpur(Sc closing rank 7475)

9. NIT Agartala (SC closing rank 33388)

10. NIT Calicut (SC closing rank 7145).

Without rank, college prediction is difficult you can refer -

https://engineering.careers360.com/jee-main-rank-predictor

Hope this will help, All the best.!!!

674 Views

jee main 2021 In 98 percentile what is my all india rank ?

Soumili Majumdar 28th Jun, 2021
Hello there,
According to your percentile, your All India Rank will be around 20000 to 23000 approximately. Since you have not mentioned your category, I'm assuming that you are from the general category. With this rank, you can get many good colleges including few NITs and IIITs too.
Also note that the cut-off rank changes every year depending on the difficulty of the paper,and the number of candidates appearing for it.

You can also predict your rank using our rank predictor. The link is given below:
https://engineering.careers360.com/jee-main-rank-predictor

You can use our college predictor to predict the best college for you:
https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

Hope this information helps you.
Good luck!!
99 Views

architecture ki liye jee main paper 1 Ka exam dena jruri hai? paper 1 or paper 2 kise kahte hai?

Anurag Khanna 13th Apr, 2021

Hello Aspirant,

No, if you want to pursue Arhitecture then you don't have to appear for Paper 1 of JEE-Main 2021 instead you have to appear JEE-Main paper 2 because Paper 1 is only for admission to B.Tech/BE courses. Exam pattern for JEE-Main 2021 for Paper 2 is described below :-

Paper 2

> Total questions = 82 {out of which you have to attempt only 77 questions for 100 marks (20 questions from Mathematics section will be of MCQs and 5 questions will have answers to be filled as a numerical value out of 10)}.

> There will be no negative marking for numerical value answers.

> Second part will be for Aptitude section which will consists of 50 compulsory questions for 200 marks and in Part third there will be two questions for Drawing test comprises of 100 marks.

> So in total paper will be of 400 marks.

For complete details about JEE-Main 2021 exam pattern kindly check out the link given below :-

https://engineering.careers360.com/articles/jee-main-exam-pattern

Some insights of JEE-Main 2021 :-

> To qualify for JEE Mains, there is no minimum aggregate percentage criteria but yes if you want to take admission into NITs, IIITs or CFTIs then you should score a minimum aggregate of 75% in your class 12th if you belongs to General/Unreserved category and 65% if you belongs to any of the reserved category.

> Also from this year according to New Education Policy the JEE-Main examination will be conducted in English, Hindi and other regional languages such as Bengali, Gujarati, Assamese, Kannada, Marathi, Punjabi, Tamil, Telugu, Urdu, Odia and Malayalam.

This year JEE-Main is being conducted with slight changes in it's pattern and it's conduction and you can check out all the changes from the link given below :-

https://engineering.careers360.com/exams/jee-main

I hope this information helps you.

Good Luck!!

42 Views

how to calculate the rank basing on percentile. any formula . for obc can you please share

Souhrid Sarkar 9th Apr, 2021
Hello,

Percentile can be calculated by :

Total Percentile (TP) = 100 x (No. of candidates appeared from the session with raw score EQUAL TO or LESS than T1 score/ Total No. of candidates appeared in the session)

For example,
Suppose, 10000 candidates will give the exam and one of the candidate secures 5th rank, His/her exam percentile will be calculated as below:

P = 10000-5/10000*100

Hence his/her percentile will be 99.95.

In the same way,you can calculate the All India Quota Rank (OBC in case for you)

Hope it helps
Thank You !!!!
203 Views

I got 96.78 percentile in Feb attempt how much rank can I expect

Koustav Dey 17th Mar, 2021

Hello,

Since, your percentile in JEE main is 96.78 it is expected that your overall rank will be around 32941 - 37030

With this rank you have chance to get seat in NIT and good government engineering colleges. Also, you will be eligible for JEE Advanced and with good rank in Advanced you can get into IITs as well.

To know your best admission possibilities use the college predictor tool from the link below

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

Good luck!

115 Views

can we give jee advance paper 2 without appear in jee main paper 1 n 2 n nata also but has score 90%in cbse board class 12 2021 plz reply me

Abir Gayen 15th Mar, 2021

Hii Aspirant,

No, you can't appear for Jee Advanced paper without appearing in the Jee main paper . There is rule of Jee Advanced paper that u can only appy in when you have qualify the cutoff marks of the jee main paper. Here cbse board marks doesn't count to apply in jee advanced paper.

Hope it Helps!!

88 Views

The ranks written in the obc cutoff catagory are obc ranks or genaral ranks?

ADITYA KUMAR Student Expert 13th Mar, 2021

Hi


I am guessing that your question is in regarding with cutoff for engineering college like NITs ,IIITs etc on our page or Josaa's page.

The cutoff rank mentioned on these pages for OBC are OBC category rank and not general/ CRL  rank.

Actually,

only for open or general category the  mentioned cutoff rank is CRL rank but for all the other categories like OBC, SC ,sT ,ews the mentioned cutoff rank is respective category rank

For previous year cut offs of top colleges like NITs, IIITs, GFTIs , you can refer our page at :-

NITs :- https://engineering.careers360.com/articles/nits-cutoff-for-top-btech-branches

IIITs:- https://engineering.careers360.com/articles/jee-main-cutoff-for-top-iiits

GFTIs :- https://engineering.careers360.com/articles/jee-main-cutoff-for-top-gftis

Or alternately you can visit our official website of josaa at

https://josaa.nic.in/Result/Result/currentorcr.aspx

To help  help you further , on analysing previous year cutoff of JEE Mains, JEE mains 2021 expected qualifying  CUT OFF percentile is given below for different categories:

.                  .  JEE      MAIN CUT   OFF    PERCENTILE

Category jeemain2020 jeemain2021 expected off


General :-     90.3765335                 90-95

GEN-EWS :-  70.2435518                  70 -75

OBC-NCL :-  72.8887969                   70 -75

SC     :-           50.1760245                  50 -55

ST :-                39.0696101                  40 - 45

PwD :-            0.0618524                      1- 2

You can check the same at our page the link is provided below

https://engineering.careers360.com/articles/jee-main-cutoff

To predict your JEE main 2021 rank you can use our rank predictor at

https://engineering.careers360.com/jee-main-rank-predictor

To have a personalised report on your chances of getting a college you can go through our college predictor, it will give you complete list of colleges which you can get on the basis of the category you belong to,  your home state, your gender etc, the link for  jee main college predictor is provided below

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

If you have any other doubt then you can always reach us to clear them :) we are always available to help you out and guide you

Thankyou

37 Views

our sons score is 96.978. what is the round figure should v calculte?

snigdha vig 13th Mar, 2021

Hi,

Congratulations for his result. According to this percentile expected rank may be around 30915 - 34753 . With this percentile he can get into good colleges. You can refer to the college predictor to get an idea about the colleges he can get in : Https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

I hope this helped you.

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